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2 years ago

DUE AT 9PM! HELP

Mathematics

1 answer:

djyliett [7]2 years ago

7 0

Answer:

$480,000

Step-by-step explanation:

Each 1,000 sq ft costs $120,000

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What is solution of 8x-2y =1 and -4x+y = 3

Maksim231197 [3]

Answer: it has no solution

Step-by-step explanation:

8x - 2y = 1 ..................... equation 1

-4x + y = 3 ...................... equation 2

solving the system of linear equation by substitution method . From equation 2 , make y the subject of the formula.

y = 3 + 4x .......................... equation 3

substitute equation 3 into equation 1 .

8x - 2(3 + 4x ) = 1

8x - 6 - 8x = 1

8x- 8x - 6 = 1

-6 = 1

this means that the equation has no solution

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=2%20%5Ctimes%202" id="TexFormula1" title="2 \times 2" alt="2 \times 2" align="absmiddle" class

EastWind [94]

4 (i literally had to think about this cause i thought it was too easy )

6 0

3 years ago

While completing a race, Will spent 14 minutes walking. If his ratio of time walking to jogging was 7 : 6, how many minutes did

worty [1.4K]

Answer:

12 minutes

Step-by-step explanation:

$\frac{7}{6} =\frac{14}{x}$

$7x=84$

$x=12$

So, he spent 12 minutes jogging.

8 0

3 years ago

Which statements are true about the place values in the number 99.999?

allsm [11]

Answers A. and B. Are correct

5 0

3 years ago

Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor

kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) Standard deviation of 23 bags

$\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167$

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

$P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)$

$= 1 - P(z < 12.57)$

Calculation the value from standard normal z table, we have,

$P(x < 5.95) = 1 - 1 = 0$

c) P( fill volume of 23 bags is below 6 ounces) = 0.001

P(x < 6) = 0.001

$P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})$

Calculation the value from standard normal z table, we have,

$P( z \leq -3.09) = 0.001$

$\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948$

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0

3 years ago