How was it like living in the 1900s-1800s

Mathematics

1 answer:

WINSTONCH [101]3 years ago

3 0

Answer:

OML

Step-by-step explanation:

How would anyone know this

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Assuming the population of interest is approximately normally distributed, construct a 95% confidence interval estimate for th

nikklg [1K]

Answer: $(17.96,20.64)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}\ \pm\ t_{n-1,\alpha/2}\dfrac{s}{\sqrt{n}}$

Given : $\overline{x}=19.3$

$s= 3.1$

n=23, which is a small sample(n<30), so we use t-test.

Significance level: $1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{22,0.025}=2.074$

Then , the confidence interval for population mean will be :-

$19.3\ \pm\ (2.074)\dfrac{3.1}{\sqrt{23}}\\\\\approx19.3\pm1.34\\\\=(19.3-1.34,19.3+1.34)\\\\=(17.96,20.64)$

Hence, the 95% confidence interval for the population mean is $(17.96,20.64)$

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3 years ago

Answer question in image

disa [49]

Answer:

Measuments

Step-by-step explanation:

Iin cooking and baking, you must put a certain amount of something. so, if you dont have that measument, then u need to find another measument to use.

7 0

2 years ago

Jonathan has been on a diet since January 2013. So far, he has been losing weight at a steady rate. Based on monthly weigh-ins,

Vlada [557]

$a)\ \ \ w(m)=-3m+205\\\\m=0\ \ \ - at\ the\ start\ of\ the\ diet\\ \\w(0)=-3\cdot0+205=205\\ \\Ans.\ weigh\ at\ the\ start\ of\ the\ diet\ is\ 205\ pounds\\ \\b)\ \ \ w(m+1)=-3(m+1)+2015=-3m-3+205=-3m+202\\ \\w(m+1)-w(m)=-3m+202-(-3m+205)=\\ \\=-3m+202+3m-205=-3\\ \\Ans.\ Jonathan\ has\ each\ month\ 3\ been\ losing \\ \\ w(m)=205-45=160\ \ \ \Rightarrow\ \ \ -3m+205=160\ \ \ \Rightarrow\ \ \-3m=-45\\ \\m=15\\ \\Ans.\ 15\ month$