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nataly862011 [7]
3 years ago
8

Name a number that has a prime factorization with three distinct factors

Mathematics
1 answer:
yanalaym [24]3 years ago
5 0
210 Has 3,5,7 As Prime Factors

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An art student wants to make a model of the classroom. The length of the classroom is 2.4 times its width. The length of the stu
Hitman42 [59]
The width should be 100.8 inches since you multiply 42 × 2.4. Hope it helps.
4 0
3 years ago
Read 2 more answers
Multiply 3/5 and 3/4
ella [17]

Answer:

6/9

Step-by-step explanation:

5 0
3 years ago
C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature
Alona [7]

Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

5 0
2 years ago
PLEASE HELP URGENT!!! 30 POINTS TO WHOEVER ANSWERS BOTH QUESTIONS!!
Alex Ar [27]
This isn’t 30 points this is 15
3 0
3 years ago
This is due in 10 minutes please help me
valkas [14]

Given:

The rate of interest on three accounts are 7%, 8%, 9%.

She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

Total interest for the year is $150.

To find:

Amount invested on each rate.

Solution:

Suppose x be the amount invested at 7%. Then,

The amount invested at 8% = 2x

The amount invested at 9% = 3x

Total interest for the year is $150.

x\times \dfrac{7}{100}+2x\times \dfrac{8}{100}+3x\times \dfrac{9}{100}=150

Multiplying both sides by 100, we get

7x+16x+27x=15000

50x=15000

Dividing both sides by 50, we get

x=\dfrac{15000}{50}

x=300

So, the amount invested at 7% is 300.

The amount invested at 8% is

2(300)=600

The amount invested at 9% is

3(300)=900

Hence, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.

7 0
2 years ago
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