In this question, there are a few kinds of the coin with a different value. To answer this question, we need to know the total coin first. The total coin count should be: 10 +20 + 15 +5= 50 coin
In this case, the coin is taken twice, that means the denominator should be 50*49. But in this question, the probablity value is 6/49, so you need to convert it into 50*49 by multiplying the numerator with 50. The value should be:
6/49 *50/50= 300/49*50
The number 300 is multiplication of 20 and 15, that mean the answer should be: 1 dimes and 1 nickles
If the total value of the coins is $15. The number of each type of coin is: 31 quarters, 72 dimes.
<h3>Number of each type of coin</h3>
Let D = number of dimes
Let Q = the number of quarters
Equations
d + q = 103
0.10d + 0.25q = 15
d = 103 -q
0.10(103 -q) + 0.25q = 15
10.3 - 0.10q + 0.25q = 15
0.15q = 4.7
q=4.7/0.15
q=31 quarters
Substitute q into second equation
D+31=103
D=72 dimes
Therefore the number of each type of coin is: 31 quarters, 72 dimes.
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Answer:
Step-by-step explanation:
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the answer is 5 pi/6.........
