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sattari [20]
3 years ago
13

Factor 4m^2 +16m+15

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
4 0

Split the second term in 4m^2 + 16m + 15 into two terms

4m^2 + 10m + 6m + 15

Factor out the common terms in the first two terms, then in the last two terms

2m(2m + 5) + 3(2m + 5)

Factor out the common term 2m + 5

(2m + 5)(2m + 3)

k0ka [10]3 years ago
3 0
<h3><u>(2m + 5)(2m + 3) is the fully factored form of the trinomial.</u></h3>

4m^2 + 16m + 15

With the way the trinomial is, we cannot factor it in it's current state.

We must check to see if splitting the middle term is possible.

<em><u>List factors of 60</u></em>

1 * 60

-1 * -60

2 * 30

-2 * -30

3 * 20

-3 * -20

4 * 15

-4 * -15

5 * 12

-5 * -12

6 * 10 (this digits satisfy the criteria for splitting the middle term.)

<em><u>Split the middle term.</u></em>

4m^2 + 6m + 10m + 15

<em><u>Group the polynomials in terms of 2.</u></em>

(4m^2 + 6m) + (10m + 15)

<em><u>Factor each binomial.</u></em>

2m(2m + 3) + 5(2m + 3)

<em><u>Rearrange the binomials.</u></em>

(2m + 5)(2m + 3)

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