How do you solve this?
1 answer:
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The larger number is 576, the smaller number is 170.
Let x = the larger number and y = the smaller number.
We know that the larger number is 406 larger than the smaller one; therefore
x = y + 406
We also know
Substituting for x we have:
When we convert mixed numbers to improper fractions, we multiply the whole number by the denominator and add the numerator:
Since the denominators are the same, we can just set the numerators equal
y+406=3y+66
We cannot have a variable on both sides, so we will subtract y from both sides:
y+406-y=3y+66-y
406=2y+66
Subtract 66 from both sides:
406-66=2y+66-66
340=2y
Divide both sides by 2:
340/2 = 2y/2
170=y
The smaller number is 170. Since the larger number is 406 larger, then it is 170+406=576.
Let x = the larger number and y = the smaller number.
We know that the larger number is 406 larger than the smaller one; therefore
x = y + 406
We also know
Substituting for x we have:
When we convert mixed numbers to improper fractions, we multiply the whole number by the denominator and add the numerator:
Since the denominators are the same, we can just set the numerators equal
y+406=3y+66
We cannot have a variable on both sides, so we will subtract y from both sides:
y+406-y=3y+66-y
406=2y+66
Subtract 66 from both sides:
406-66=2y+66-66
340=2y
Divide both sides by 2:
340/2 = 2y/2
170=y
The smaller number is 170. Since the larger number is 406 larger, then it is 170+406=576.
If we write where we see
in the equation and set the result equal to
, we get the result.