If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)

Mathematics

1 answer:

Elina [12.6K]1 year ago

4 0

If we write $k$ where we see $x$ in the equation and set the result equal to $-10$ , we get the result.

$f(k)=k(k)^3+k^2-k(k)+2$
$=k^4+k^2-k^2+2$
$=k^4+2=-10$
$k^4=-12$
$k_{1}=\sqrt[4]{3}(-1-i)$
$k_{2}=\sqrt[4]{3}(-1+i)$
$k_{3}=\sqrt[4]{3}(1-i)$
$k_{4}=\sqrt[4]{3}(1+i)$

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