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Savatey [412]
1 year ago
12

If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (k, -10)

Mathematics
1 answer:
Elina [12.6K]1 year ago
4 0

If we write k where we see x in the equation and set the result equal to -10, we get the result.

  • f(k)=k(k)^3+k^2-k(k)+2
  • =k^4+k^2-k^2+2
  • =k^4+2=-10
  • k^4=-12
  • k_{1}=\sqrt[4]{3}(-1-i)
  • k_{2}=\sqrt[4]{3}(-1+i)
  • k_{3}=\sqrt[4]{3}(1-i)
  • k_{4}=\sqrt[4]{3}(1+i)

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Step-by-step explanation:

first lets add the two equations. add the x's, add the y's, add the constants on the right.

we get

0x - 1y = -10

so then divide --10 by -1 because we do the opposite operations to both sides

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now substitute y = 10 into the first equation

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and then we get -10x - 90 = 10

now add 90 to both sides

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divide 100 by -10

x = -10

y = 10

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