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cupoosta [38]
3 years ago
9

Write one digit on each side of 23 to make a four digit multiple of 72. How many different solutions does this problem have?

Mathematics
1 answer:
user100 [1]3 years ago
5 0

Answer:

This problem has two possible solutions.

2232

7236

Step-by-step explanation:

To be divisible by 72, a number has:

To be divisible by both 8 and 9 at the same time.

It is divisible by 8 if it's last two digits are divisible by 4.

It is divisible by 9 it the sum of it's digits is a number divisible by 9.

a23b

3b must be divisible by 4. In the thirties, the numbers that are divisible by 4 are 32 and 36. So b = 2 or b = 6.

a232

2 + 3 + 2 = 7

The higest possible value of a is 9 and the lowest is 1.

Between 8 and 16, only 9 is divisible by 9. So a = 2.

a = 2, b = 2 is one of the solutions.

a236

2 + 3 + 6 = 11

The higest possible value of a is 9 and the lowest is 1.

Between 12 and 20, only 18 is divisible by 9. So we need a = 7

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3x + 4y=17<br>- 4x – 3y = - 18​
OleMash [197]

Answer:

3

Step-by-step explanation:

6 0
2 years ago
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You spent $10 on office supplies out of a $25 budget.What percent of your budget did you spend?
lana66690 [7]
You spent 40% of your budget. 

10/25=2/5=40/100
6 0
2 years ago
Sketch the points (0,5,2),(4,0,-1),(2,4,6) and(1,-1,2) o a single set of coordinate axes?
nordsb [41]

Explanation:

As points have three coordinates i.e. x, y and z hence the sketch of the given four points is drawn in 3D shape and for that picture is attached here with this answer.

Points are given in the format as below

(value of x-coordinate , value of y-coordinate , value of z-coordinate)

In the attachment:

Point A = (0,5,2) (in blue color)

Point B = (4,0,-1) (in purple color)

Point C = (2,4,6) (in orange color)

Point D = (1,-1,2) (in black color)

7 0
2 years ago
the length of a rectangle is 5 inches more then the width. the area of the rectangle is equal to 2 inches more than 4 times the
Svet_ta [14]
P = 2(L + W)
L = W + 5
A = 4P + 2

P = 2(W + 5 + W)
P = 2(2W + 5)
P = 4W + 10

A = 4P + 2
A = 4(4W + 10) + 2
A = 16W + 42

A = L * W
A = W(W + 5)
A = W^2 + 5W

W^2 + 5W = 16W + 42
W^2 + 5W - 16W - 42 = 0
W^2 - 11W - 42 = 0
(W + 3)(W - 14) = 0

W - 14 = 0
W = 14 <==

L = W + 5
L = 14 + 5
L = 19 <==

P = 2(19 + 14)
P = 2(33)
P = 66

A = L * W
A = 19 * 14
A = 266

answer : length = 19, width = 14....perimeter = 66....area = 266
5 0
3 years ago
The length around the outside of semicircle O from point L through point M to point N is 14 centimeters. The perimeter of semici
Luden [163]
The area would be 83.67 cm.

A semicircle is half of a circle.  The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle.  The formula for circumference is:

C=πd

Using our information, we have  

22.92 = 0.5(3.14)d
22.92 = 1.57d

Divide both sides by 1.57:

22.92/1.57 = 1.57d/1.57
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Since the diameter is 14.6, the radius is 14.6/2 = 7.3.

We use the radius for the area of the semicircle:

A=0.5πr²
=0.5(3.14)(7.3)²
=83.67
3 0
3 years ago
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