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cupoosta [38]
3 years ago
9

Write one digit on each side of 23 to make a four digit multiple of 72. How many different solutions does this problem have?

Mathematics
1 answer:
user100 [1]3 years ago
5 0

Answer:

This problem has two possible solutions.

2232

7236

Step-by-step explanation:

To be divisible by 72, a number has:

To be divisible by both 8 and 9 at the same time.

It is divisible by 8 if it's last two digits are divisible by 4.

It is divisible by 9 it the sum of it's digits is a number divisible by 9.

a23b

3b must be divisible by 4. In the thirties, the numbers that are divisible by 4 are 32 and 36. So b = 2 or b = 6.

a232

2 + 3 + 2 = 7

The higest possible value of a is 9 and the lowest is 1.

Between 8 and 16, only 9 is divisible by 9. So a = 2.

a = 2, b = 2 is one of the solutions.

a236

2 + 3 + 6 = 11

The higest possible value of a is 9 and the lowest is 1.

Between 12 and 20, only 18 is divisible by 9. So we need a = 7

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3 years ago
The federal government covers a period called a _____ year??
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3 years ago
H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.
natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

(h+k)(2)=2^2+1+2-2

(h+k)(x)=5

2)The value of the function (h-k)(3),

(h-k)(x)=h(x)-k(x)

(h-k)(x)=x^2+1-x+2

(h-k)(3)=3^2+1-3+2

(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

3h(x)+2k(x)=3x^2+3+2x-2\times 2

3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2

3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0
2 years ago
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