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True [87]
3 years ago
9

What is the slope of (29, 19) and (14, 36)

Mathematics
1 answer:
o-na [289]3 years ago
6 0
Formula for the slop is:
m=∆y/∆x.

m=(36-19)/(14-29)
m=-17/15. As a result, the slope will be -17/15. Hope it help!
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Find the slope of the line passions through the points(-6,3) and (-6,-1)
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Answer:

The slope of this line would be undefined.

Step-by-step explanation:

In order to find the slope of any line, use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (3 - -1)/(-6 - -6)

m = (3 + 1)/(-6 + 6)

m = 4/0

Since we cannot divide by 0, then we know the slope is undefined.

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The function g is defined as follows.
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Answer:

h(x) =  2x²+2

Step-by-step explanation:

Given the function g is defined as follows.

g(x) = 2x²+7

If the graph is translated by 5units vertically downwards, this means that the function will be reduced by 5 units to have;

h(x) =  2x²+7 - 5

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Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of vector QP .
Katyanochek1 [597]

Answer:

a)The component form is

\vec {QP}=\binom{ - 1}{ - 8}

b)The magnitude is √65

c) <2,14>

Step-by-step explanation:

Recall that:

\vec {QP}=\vec {OP}-\vec{OQ}

We substitute the position vectors to get:

\vec {QP}=\binom{ - 8}{7} -  \binom { - 7}{15}

We subtract the corresponding components to obtain:

\vec {QP}=\binom{ - 8 -  - 7}{7 - 15}

This gives:

\vec {QP}=\binom{ - 8  + 7}{7 - 15}

This simplifies to:

\vec {QP}=\binom{ - 1}{ - 8}

The magnitude of a vector in the component form:

\binom{x}{y}

is

\sqrt{ {x}^{2}  +  {y}^{2} }

This means:

|\vec {QP}|= \sqrt{ {( - 1)}^{2}  +  {( - 8)}^{2} }

This simplifies to:

|\vec {QP}| = \sqrt{ 1 +  64 }

|\vec {QP}| = \sqrt{ 65 }

c) We have the vectors u = <4, 8>, v = <-2, 6>.

We want to find:

u+v

This implies that:

u+v=<4,8>+<-2,6>

We add the corresponding components to get;

u+v=<4+-2,8+6>

This simplifies to:

u+v=<2,14>

7 0
3 years ago
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