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Ilya [14]
3 years ago
13

ADDISON EARNED TWENTY FIVE DOLLARS, GAVE 18 TO A FRIENED MATH QUESTION

Mathematics
2 answers:
ryzh [129]3 years ago
6 0
$25-$18 would be $7 does this  help?
jenyasd209 [6]3 years ago
5 0
The question is a subtraction problem. 

We know that Addison earned 25 dollars and gave 18 to his friend. 

We can solve this problem by making an equation : x=25-18 

Solve for x 

x=25-18 

25-18 = 7 

x=7 

Therefore, Addison has 7 dollars left. 
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Write an equation for the quadratic graphed below
uranmaximum [27]

Answer:

Step-by-step explanation:

LOL The graph doesn’t match the y intercept :)

Anyway

If we have point (0,-3) we have a quadratic of

y=ax^2+bx-3 we are given points (-1,0) and (2,0) so

a-b-3=0 and 4a+2b-3=0

4a+2b-3+2(a-b-3)=0

4a+2b-3+2a-2b-6=0

6a-9=0

6a=9

a=1.5, since a-b=3

1.5-b=3

b=-1.5

y=1.5x^2-1.5x-3

6 0
3 years ago
Read 2 more answers
UNIT PRICE TASK CARD #3
12345 [234]
0.015546875 is the exact amount you pay per fluid oz.
3 0
2 years ago
Read 2 more answers
Ava has 34 candy bars. If
aliya0001 [1]

\bf Step-by-step~explanation:

If Ava has 34 candy bars, and each box can hold 5 bars, then we need to find out how many boxes that are filled up.

\bf Step~1:

Divide the number of candy bars (34), by the number each box can hold (5)

\bf\frac{34}{5}=6.8

Since we cannot have 6.8 boxes, we have to round down to 6.

\boxed{\bf Our~final~answer:~6~boxes}

\bf Check~our~answer:

To check our answer, we multiply the number of boxes (6), by the number of bars in each box (5), to get 30. We add Ava's extra bars (4), and we get the number we started off with: 34. This proves our answer is correct!

4 0
3 years ago
2 Which expression is equivalent to 64-*?
Rasek [7]

Answer:

2

Step-by-step explanation:

(8-x)(8+x)

8×8=64

-x·+x=-x^2

64-x^2

3 0
2 years ago
A sample size of n = 64 is drawn from a population whose standard deviation is o = 5.6.
AlekseyPX

Answer:

The margin of error for a 99% confidence interval for the population mean is 1.8025.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem:

\sigma = 5.6

So

M = 2.575*\frac{5.6}{\sqrt{64}} = 1.8025

The margin of error for a 99% confidence interval for the population mean is 1.8025.

5 0
2 years ago
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