Answer:
True, False, False, False
Step-by-step explanation:
I'll find the lengths of all sides of the drawing before answering individual answers so that it's less confusing.
1) The question says that QR is a perpendicular bisector of TS. This means that the length of TQ and QS is the same. Also, since both triangles TRQ and SRQ share the same side RQ, and the angle between the two segments is 90 degrees, the two triangles are congruent (RTQ and RSQ) using SAS.
2) Side RT and TS will have the same length since the two triangles are congruent. (2x+1) = (4x-3) --> -2x = -4 --> x = 2. We can conclude that x = 2.
3) Now that we know that x = 2, we can find the length of side RS by replacing the x with 2. 4(2)-3 is 5, so RS = 5.
4) We can use the Pythagorean theorem to find RQ (Hypotenuse^2 = Other two sides added after being squared individually). Since the hypotenuse of triangle RSQ is RS which is 5, and one side is 4, we can input those into our equation. (5)^2 = (4)^2 + (RQ)^2. --> 25 = 16 + (RQ)^2 --> 9 = (RQ)^2 --> RQ = 3.
5) Since the two triangles RTQ and RSQ are congruent, side TQ and SQ also have the same length, since CPCTC (Corresponding parts of congruent triangles are congruent). QS is 4, so TQ will also be 4. This means that ST will be 8 (4+4). ST = 8
Now that we have all the clues, all we need to do is choose True or False.
RS = 5 is TRUE
RS = 4 is FALSE
ST = 10 is FALSE
QR = 4 is FALSE
Repeating because its repeating 91.
If the '7t' is supposed to be '7y', then the answer is below
(4y+8)-(7y-12)=11
distribute the negative into the second parenthesis
4y+8-7y+12=11
combine like terms
-3y+20=11
subtract the 20 from both sides
-3y=-9
divide by -3 on both sides
y=3
if it is supposed to be '7t', I'm not sure if there's enough information
Answer:
C
Step-by-step explanation:
2x + 3(x - 10) = 45
2x + 3x - 30 = 45
5x - 30 = 45
5x = 75
x = 15
When a teacher gives a test with questions that fall into 3 levels of difficulty (easy, moderate, and hard) The scoring method that would best allow her to identify the students who need help is:
B. weight each question by its difficulty: 1 for easy, 2 for moderate, and 3 for hard.