Answer:
82ibs - 40ibs = 22ibs
Step-by-step explanation:
Complete question :
Write a system of equations, with one equation describing the cost to bowl at Bowl-o-Rama and the other describing the cost to bowl at Bowling Pinz. For each equation, let x represent the number of games played and let y represent the total cost.
Bowl-O-Rama rents shoes for $2 and each game cost $2.50
Bowling Pinz rents shoes for $4 and each game cost $2
Answer:
Bowl-O-Rama:
y = $2 + $2.50x
Bowling pinz:
y = $4 + $2x
Step-by-step explanation:
The total cost is the sum of shoe rental plus the product of the unit game rate and the number of games played.
Total cost, y
x = number of games played
Bowl-O-Rama:
y = Shoe rent + (unit rate per game * number of games)
y = $2 + ($2.50 * x)
y = $2 + $2.50x
Bowling Pinz :
y = Shoe rent + (unit rate per game * number of games)
y = $4 + ($2 * x)
y = $4 + $2x
Rent: $ 780
Food:$ 900
Medical:$ 450
Clothes:$ 300
Miscellaneous:$ 570
Answer:
11 1/12
Step-by-step explanation:
6 1/3 = 19/3
7 1/4 = 29/4
2 1/2 = 5/2
19/3 + 29/4 - 5/2
We must find the LCM of 3, 4, and 2. This happens to be 12
3*4 = 12
4*3 = 12
2*6 = 12
Multiply each fraction by the factor that'll get it to 12.
19/3 * 4/4 = 76/12
29/4 * 3/3 = 87/12
5/2 * 6/6 = 30/12
Now go through the problem
76/12 + 87/12 - 30/12
76 + 87 = 163
163/12 - 30/12
163 - 30 = 133
133/12
Simplify
133/12 = 11.0833... or 11 1/12
Hope this helps.
