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IRISSAK [1]
3 years ago
11

a car traveled at an average speed of 80 miles per hour for 3 hours and consumes fuel at a rate of 34 miles per gallon

Mathematics
1 answer:
Dimas [21]3 years ago
7 0
As an example I will finish this problem statement for you:

"<span>A car traveled at an average speed of 80 miles per hour for 3 hours and consumes fuel at a rate of 34 miles per gallon.  How many gallons of fuel will the car use on this trip?

Distance traveled is (80 mph)(3 hrs) = 240 miles.

How many gallons of gas did the car consume?

240 miles        1 gallon
-------------- * -------------- =  7.06 gallons (approx)
        1            34 miles</span>
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Please help
pychu [463]

Answer:

<h2>        y = x² - 1</h2>

Step-by-step explanation:

y = -1 for x = 0 {point(0, -1)} means -1 at the end of formula

If we add 1 to y-coordinate of  every given point we get the squares of x-coordinate:

(1, 0):   1² - 1 = 0

(2, 3):   2² - 1 = 4 - 1 = 3

(3, 8):   3² - 1 = 9 - 1 = 8

(4, 15):   4² - 1 = 16 - 1 = 15

So for any x:

(x, y)   y = x² - 1

6 0
3 years ago
ANSWER ASAP!
morpeh [17]

Answer:

vvvvvcvv

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
Write the phrase "one more than the product of six and nine" as a mathematical expression.
frosja888 [35]

Answer:

<em>C. 6 ⋅ 9 + 1 </em>

Step-by-step explanation:

Start with the multiplication:

"one more than the product of six and nine"

6 ⋅ 9

Now take care of the addition by adding 1 to the product.

"one more than the product of six and nine"

6 ⋅ 9 + 1

Answer: C. 6 ⋅ 9 + 1

4 0
3 years ago
What is 0.3 repeating as a fraction in simplest form
NeTakaya
The answer is 3/9 or 1/3 in its simplest form
4 0
3 years ago
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