Answer:
See the answer below
Explanation:
<em>The DNA of eukaryotic organisms being present in the nucleus while the protein-synthesizing organelle, the ribosome being present in the cytoplasm poses a spatial problem. It means that transcribed DNAs (messenger RNA) in the nucleus would have to somehow be transported to the ribosome in order for the cell to successfully synthesize proteins.</em>
The problem of transporting the messenger RNA is solved by two features of the cell:
- The presence of pores in the nuclear envelop
- The presence of transport proteins in the nucleus
<u>The mRNA binds to the transport proteins to form mRNA-protein complexes and is transported through the nuclear pores, often with the assistance of ATP. </u>
Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
Answer:
The tall parent was heterozygous
Explanation:
If tall height is dominant to short height the only genotype possible for short height is hh, while there are two possible genotypes for tall height, Hh and HH. When HH is crossed with hh all the offspring are Hh, but if Hh is crossed with hh, a quarter of the offspring is HH, a quarter is hh and half is Hh. If the tall pea plants were HH there would only be tall offspring, but because there are some short offspring we know that the tall pea plants must have a genotype of Hh.
Answer: burning processes, such as backyard burning and commercial or municipal waste incineration.
the use of fuels, such as wood, coal, or oil.
natural phenomena, such as volcanic activity and forest fires.
industrial processes, such as chlorine bleaching of paper pulp and smelting.
Explanation:
Hope I gave you the answer you are looking for :) LMK