Answer:
The total cost is 1.25 dollars.
Step-by-step explanation:
The reaction between HCl and CaCO₃ is giving by:
2HCl(aq) + CaCO₃(s) → CaCl₂(aq) + CO₂(g) + H₂O(l) (1)
0.500L M: 100.01g/mol
0.400M
According to equation (1), 2 moles of HCl react with 1 mol of CaCO₃, so to neutralize HCl, we need the next amount of CaCO₃:
The CaCO₃ mass of each tablet is:
![m CaCO_{3} = 1 g_{tablet} \cdot \frac{40g CaCO_{3}}{100g_{tablet}} = 0.4g](https://tex.z-dn.net/?f=%20m%20CaCO_%7B3%7D%20%3D%201%20g_%7Btablet%7D%20%5Ccdot%20%5Cfrac%7B40g%20CaCO_%7B3%7D%7D%7B100g_%7Btablet%7D%7D%20%3D%200.4g%20)
Hence, the number of tablets that we need to neutralize the HCl is:
Finally, if every 80 tablets costs 4.00 dollars, 25 tablets will cost:
![cost = (\frac {4 dollars}{80 tablets}) \cdot 25 tablets = 1.25 dollars](https://tex.z-dn.net/?f=%20cost%20%3D%20%28%5Cfrac%20%7B4%20dollars%7D%7B80%20tablets%7D%29%20%5Ccdot%2025%20tablets%20%3D%201.25%20dollars%20)
<u>So, the total cost to neutralize the HCl is 1.25 dollars.</u>
I hope it helps you!