How much taller was Mt. Everest determined to be in 1999, than in 1852? 11 meters 12 meters 22 meters 147 meters

Mathematics

1 answer:

katen-ka-za [31]3 years ago

7 0

Answer:

11 meters

Step-by-step explanation:

In 1852 its height was 29.002ft or 8.839m, while the measuring in 1999 said that it was 29.035ft or 8.850m. That means that it is taller by some 11 meters or 33 feet. That is because it keeps increasing its size since its positioned on such plates that hit each other.

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What is the center of the circle that you can circumscribe about a triangle with vertices A(2, 6), B(2, 0), and C(10, 0)?

denis23 [38]

The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle (x,y):
$d^2 = (x-x_0)^2 + (y-y_0)^2$
Plugging in points A and B into distance formula, then setting them equal to each other gives:
$(x-2)^2+(y-6)^2 = (x-2)^2 + y^2$
Right away we can cancel out the x terms leaving:
$(y-6)^2 = y^2$
Expand Left side and Solve for y:
$y^2 -12y +36 = y^2$
$y = 3$
Plug in points B and C as before:
$(x-2)^2 + y^2 = (x-10)^2 + y^2$
Here we can cancel the y-terms.
Expand and solve for x:
$x^2 -4x+4 = x^2 -20x+100$
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6 0

3 years ago

10(x – 9) > -270<br> How do I do this ?

Ilia_Sergeevich [38]

Answer:

x > -18

Step-by-step explanation:

10 ( x - 9 ) > -270

Treat the inequality like an equation,

Distribute first:

10 ( x - 9 ) > - 270

10x - 90 > -270