Help pleaseeee Hajsbdheuebebbdhdjwiwkwkwjdfbfjdjdje Idk what to do

Mathematics

1 answer:

GREYUIT [131]3 years ago

7 0

Answer:

Step-by-step explanation: square root both numbers so 55 square root is 7.41 and he square root of 16 is 4 now divide them so 7.41 divided by 4 = to 1.85 there fore 1.85 is ur answer

You might be interested in

In order to lower his monthly auto insurance bill, Henry has decided to change his existing policy by increasing the deductible

Ronch [10]

Hello, The answer to this question is, A. $12.48

3 0

3 years ago

Read 2 more answers

Alcohol consumption tends to cause what kind of behavior

kirza4 [7]

Agressive behavior is my best guess

3 0

3 years ago

Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.

andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

The equation is given as: $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that $\mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}$ has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962