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4 years ago

Que compuestos representan el enlace covalente

Chemistry

1 answer:

PolarNik [594]4 years ago

8 0

I really would like to answer it but I can’t read Spanish represent?

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What is the term for the amount of space occupied by an object?

Rzqust [24]

Answer: Volume

Explanation:

Cos Milky said it. Milky smart.

5 0

3 years ago

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What is the molarity of a solution which has a volume of 3 litres and contains 5.1 moles of Br2?

katrin [286]

Answer:

The molarity of the solution is 1.7 $\frac{moles}{liter}$ .

Explanation:

Molarity (M) or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

$Molarity=\frac{moles of solute}{volume of the solute}$

Molarity is expressed in units $\frac{moles}{liter}$ .

In this case, you know:

moles of solute= 5.1
volume= 3 L

Replacing:

$Molarity=\frac{5.1 moles}{3 L}$

Solving:

Molarity= 1.7 $\frac{moles}{liter}$

The molarity of the solution is 1.7 $\frac{moles}{liter}$ .

4 0

3 years ago

A solution is made by dissolving

nikklg [1K]

Answer:

THE MOLARITY IS 2.22 MOL/DM3

Explanation:

The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water

Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol

Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;

37.5 g of Na2S = 217 g of water

( 37.5 * 1000 / 217 ) g = 1000 g of water

So, 172.81 g/dm3 of the solution

So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass

Molarity = 172.81 g/dm3 / 78 g/mol

Molarity = 2.22 mol/dm3

The molarity of the solution is 2.22 mol/dm3

4 0

4 years ago

Help ASAP loll Will give Brainly

attashe74 [19]

This is correct what do you need help in?

4 0

3 years ago

C5h12 with one tertiary carbon

AfilCa [17]

Answer:

See attached image.

Explanation:

Hello there!

In this case, according to the isomeric structure of hydrocarbons, it is possible to draw a five-carbon hydrocarbon with a tertiary carbon by keeping in mind these tertiary carbons are characterized by the presence of three bonds with carbon atoms.

In such a way, as shown on the attached image, the second carbon from left to right is tertiary because of the aforementioned, and also, the compound has five carbon atoms and twelve hydrogen atoms.

Best regards!

3 0

3 years ago