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3 years ago

Name at least two benefits of using models in science.

Chemistry

2 answers:

aliina [53]3 years ago

7 0

Explanation:

1) it gives you a visual of what you will be doing

2) you can find more variables when looking at it compared to just thinking of it

3) gives you new insights on what is yet to come

4) allows you to answer some questions and begin testing

makkiz [27]3 years ago

3 0

Answer:

Models make concepts more tangible. They also make it possible to notice patterns, develop or revise representations, and predict or explain events or relationships.

Explanation:

Sample answer from edg

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You need to produce a buffer solution that has a pH of 5.03. You already have a solution that contains 10. mmol (millimoles) of

mario62 [17]

Explanation:

We have given the acid that is, acetic acid. It is known that acetic acid is a weak acid.

Therefore, formula that depicts relationship between pH, $pK_{a}$ and weak acid is as follows.

pH = $pK_{a}$ + log $\frac{[A^{-}]}{[HA]}$

where, [HA] = concentration of weak acid

$[A^{-}]$ = concentration of conjugate base of given weak acid

Since, we have to calculate the concentration of conjugate base of acetic acid. So, let it be equal to x. Whereas concentration of acetic acid is 10 mmol, $pK_{a}$ is 4.74 and pH is 5.03.

Hence, putting these values in the above formula as follows.

pH = $pK_{a}$ + log $\frac{[A^{-}]}{[HA]}$

5.03 = 4.74 + log $\frac{x}{10}$

$\frac{x}{10}$ = antilog (0.29)

x = 19.4 mmol

Thus, we can conclude that there is 19.4 mmol acetate (the conjugate base of acetic acid) will be needed to add to this given solution.

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3 years ago

What is the symbol for nitrogen? a. 7 b. n c. 14.01 d. nitrogen

Oksana_A [137]

The correct answer is B.N

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4 years ago

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sergij07 [2.7K]

Answer:

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4 years ago

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Maybe someone can help me out with this or give me the equation to find mols/liters - thanks to if you can help, here's the ques

zvonat [6]

Answer :The correct answers are :

Concentration in one can soup : Table salt = 6.12 $\frac{mol}{L}$

Table sugar = 5.84 $\frac{mol}{L}$

Concentration in one bowl Soup : Table salt = 3.82 $\frac{mol}{L}$

Table sugar = 3.65 $\frac{mol}{L}$

Concentration : It is quantity to measure a solution . It can be defined as abundance of constituents per volume of solution . The most used concentration is molar concentration .

Molar concentration is defined as mole of solute present in volume of solution . The unit of concentration is $\frac{mol}{L}$ . It is expressed as :

$Concentration ( \frac{mol}{L} ) = \frac{mole of solute (mol)}{Volume of solution (L)}$

Concentration in one can of soup (Volume = 250 mL )

Volume of one can soup = 250 mL . Converting it from mL to L as :

(1 L = 1000mL)

$Volume of one can soup = \frac{250 mL}{1000mL} * 1 L = 0.250 L$

A) Concentration of table salt :

Following are the steps to find out molar concentration :

Step 1 : Find mass of solute :

Since mass of solute is not given , so we take solubility of NaCL in 1 L of water . Solubility is maximum amount of NaCL that can be dissolved in 1 L water at room temperature . From image , we can say that 359 g of NaCL can be dissolved ideally in 1 L of water .

Since volume of solution is 0.250 L , so mass of salt in 0.250 L can be found :

Mass of NaCL in 1 L = 359 g

Mass of NaCL in 0.250 L of water = 359 g * 0.250 L

Mass of NaCL in 0.250 L = 89.75 g

Step 2 : Convert mass of solute to its mole

Mole can be calculate from mass as :

$Mole (mol) = \frac{given mass (g) }{molar mass \frac{g}{mol}}$

Molar mass of Table salt (given ) = 58.44 $\frac{g}{mol}$

plugging value of mass and molar mass in mole formula :

$Mole = \frac{89.75 g }{58.44 \frac{g}{mol}}$

Mole of Table salt = 1.53 mol

Step 3 : To find concentration .

Mole of solute = 1.53 mol

Volume of solution ( one can of soup ) = 0.250 L

Plugging these values in Concentration formula :

$Concentration = \frac{1.53 mol}{0.250 L}$

Concentration of Table salt in one can soup = 6.12 $\frac{mol}{L}$

B) Concentration of Table sugar :

Following steps can be used :

Step 1: To find mass of Table sugar

Since mass of sugar is not given , so solubility of sugar will be considered . From image solubility is 2000 g in 1 L of water .

Since volume of one cup soup is 0.250 L , so mass of Sugar in 0.250 L of solution =

Mass of sugar in 1 L of water = 2000 g

Mass of sugar in 0.250 L of solution = 2000 g* 0.250 L

Hence , mass of Sugar in 0.250 L of solution = 500 g

Step 2 : To convert mass of sugar to its mole

Mass can be converted to mole using same formula. Plugging value in mole formula :

$Mole of sugar = \frac{500 g}{342.3 \frac{g}{mol}}$

Mole of sugar = 1.46 mol

Step 3 : To find concentration of Sugar :

Mole of sugar = 1.46 mol

Volume of solution = 0.250 L

Plugging these values in concentration formula :

$Concentration = \frac{1.46 mol}{0.250 L} = 5.84 \frac{mol}{L}$

-----------------------------------------------------------------------------------------------------------

Concentration in one bowl of soup :

Volume of one bowl of soup = 150 mL water + 250 mL of one can soup

= 400 mL

Converting mL to L : ( 1 L = 1000mL )

$Volume of solution = \frac{400 mL}{1000mL} * 1 L$

Volume of solution = 0.400 L

A) Concentration of Table salt :

Similar steps will be used :

Step 1: T find mass of Table salt

Again solubility will be used , which is =359 g in 1 L .Since 150 mL water is added which had no salt . hence all the salt was present in 250 mL one can soup , so mass of salt present in one can soup will be used .

Mass of Table salt = 89.75 g

Step 2: To convert mass to mole

Mass can be converted using mole formula .

Mole of Table salt = 1.53 mol ( calculated above )

Step 3: To find concentration

Mole of Table salt = 1.53 mol

Volume of one bowl soup = 0.400 L

Plugging these values in Concentration formula as:

$Concentration = \frac{1.53 mol}{0.400 L }$

Concentration of Table salt in one bowl soup = 3.82 $\frac{mol}{L}$

B) Concentration of Table sugar :

Step 1 : To find mass of Table sugar

Mass of sugar in 0.400 L will be same as that of mass of sugar present in 0.250 L since water had no sugar .

Mass of Table sugar = 500 g

Step 2 : To convert mass to mole

Mole can be calculated using mole formula ( as calculated above for one can soup )

Mole of Table sugar = 1.46 mol

Step 3: To find concentration

Mole of Table sugar (solute ) = 1.46 mol

Volume of one bowl soup = 0.400 L

Plugging these values in concentration formula :

$Concentration = \frac{1.46 mol}{0.400 L}$

Concentration of Table sugar in one bowl soup = 3.65 $\frac{mol}{L}$

----------------------------------------------------------------------------------------

Also Note :You have marked Table sugar as Ionic which is incorrect .Table sugar is covalent as it has all non metals .

8 0

4 years ago

Please help :) brainliest and +10 pts

Ludmilka [50]

Im guesing D but if im not right im sorry i know it its just i dont remember?!

8 0

3 years ago

Read 2 more answers