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3 years ago

During which season at what latitude does the sun not set

Physics

2 answers:

Allisa [31]3 years ago

8 0

The sun not set in the summer and greater than 66 N

I hope that's help !

horsena [70]3 years ago

4 0

Answer:

In summer season, sun would not set at latitude 66.5 N and above. In summer season for southern hemisphere, sun would not set for latitude 66.5 S and above.

Explanation:

Season on Earth occurs due to the inclination of the axis about which it rotates. Due to this, there is different length of day and night in different hemispheres at a time.

Sun is highest in the sky in northern hemisphere in summers. So the places at 66.5 N and higher latitude experience 24 hours sun light.

Similarly, in northern hemisphere summers, places at 66.5 S and higher latitude experience 24 hours sun light.

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3 years ago

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Ket [755]

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a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

Explanation:

Let consider the bottom of the first floor in a building as the zero reference ( $z = 0\,m$ ). The change in potential energy experimented by a particle ( $\Delta U_{g}$ ), measured in joules, is:

$\Delta U_{g} = m\cdot g\cdot (z_{f}-z_{o})$ (1)

Where:

$m$ - Mass, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

$z_{o}$ , $z_{f}$ - Initial and final height with respect to zero reference, measured in meters.

Please notice that $m\cdot g$ is the weight of the particle, measured in newtons.

a) If we know that $m = 3\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ , $z_{o} = 0\,m$ and $z_{f} = 4.1\,m$ , then the change in potential energy is:

$\Delta U_{g} = (3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.1\,m-0\,m)$

$\Delta U_{g} = 120.626\,J$

The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) If we know that $m\cdot g = 650\,N$ , $z_{o} = 4.1\,m$ and $z_{f} = 0\,m$ , then the change in potential energy is:

$\Delta U_{g} = (650\,N)\cdot (0\,m-4.1\,m)$

$\Delta U_{g} = -2665\,J$

The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

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3 years ago