What is the equation process to this question?
1 answer:
![h(t) =-16t^2 + 80t + 4,\quad 0 \le t \le 5.04](https://tex.z-dn.net/?f=h%28t%29%20%3D-16t%5E2%20%2B%2080t%20%2B%204%2C%5Cquad%200%20%5Cle%20t%20%5Cle%205.04)
(a) Find the height of the ball (in feet) above the ground 2 s after its released.
That's just h(2)
h(2) = -16(2²) + 80(2) + 4 = -64 + 160 + 4 = 100
Answer: 100 feet
(b) Find the height of the ball (in feet) above the ground 4 s after its released.
That's just h(4)
h(4) = -16(4²) + 80(4) + 4 = -256 + 320 + 4 = 68
Answer: 68 feet
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Step-by-step explanation:
The Answer is
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Step-by-step explanation:h311