ASAP PLEASE Find the volume of the solid generated by revolving about the y-axis the region bounded by the given equations

The price of a 7-minute phone call is $2.45. What is the price of a 13-minute phone call?

Umnica [9.8K]

If 7 minutes is $2.45, then 13 minutes is $4.55 cuz 1 minute is 0.35 cents

5 0

3 years ago

Read 2 more answers

51 is 33 1/3 of what number?

nevsk [136]

Answer:

$\boxed{\frac{153}{100}\:\:Or\:\:1.53}$

Step-by-step explanation:

Let the number be $n$ .

Then,

$33\frac{1}{3} \tmes n=51$

This implies that;

$\frac{100}{3} n=51$

We multiply both sides by $\frac{3}{100}$ to obtain;

$\frac{3}{100} \times \frac{100}{3}n=\frac{3}{100} \times 51$

$\Rightarrow n=\frac{3}{100} \times 51$

$\Rightarrow n=\frac{153}{100}$

Or

$\Rightarrow n=1.53$

5 0

3 years ago

Read 2 more answers

Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to

ra1l [238]

Answer:

The confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 41

For a 95% confidence the level of significance is $\alpha = [100 - 95]\% = 0.05$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96$

For a 90% confidence the level of significance is $\alpha = [100 - 90]\% = 0.10$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645$

So we see with decreasing confidence level the critical value decrease

Now the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }$

given that other values are constant and only $Z_{\frac{\alpha }{2} }$ is varying we have that

$E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Hence for reducing confidence level the margin of error will be reducing

The confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower

3 0

2 years ago

Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (

Vladimir79 [104]

Answer:

Factors: $(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

Step-by-step explanation:

We are given a polynomial:

$f(x)=x^4-x^3-2x-4$

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

$f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

8 0

2 years ago

Mr. Carter drove 638 miles the first weekend. He drove 243 miles the second weekend.

zaharov [31]

638-243 = 395 miles

rounding up, it would be 400 miles

7 0

2 years ago

Read 2 more answers