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Effectus [21]
3 years ago
12

CAN SOMEONE PLEASE JUST ANSWER THIS ASAP FOR BRAINLIEST!!!

Mathematics
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:

Im pretty sure that the answer is a.

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The area of the sphere is equal to xpie cm square. find it volume<br><br>PLEASE HELP!​
Talja [164]

Answer:

not enough information

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Anettt [7]

Answer:

Choice C: approximately 121 green beans will be 13 centimeters or shorter.

Step-by-step explanation:

What's the probability that a green bean from this sale is shorter than 13 centimeters?

Let the length of a green bean be X centimeters.

X follows a normal distribution with

  • mean \mu = 11.2 and
  • standard deviation \sigma = 2.1.

In other words,

X\sim \text{N}(11.2, 2.1^{2}),

and the probability in question is X \le 13.

Z-score table approach:

Find the z-score of this measurement:

\displaystyle z= \frac{x-\mu}{\sigma} = \frac{13-11.2}{2.1} = 0.857143. Closest to 0.86.

Look up the z-score in a table. Keep in mind that entries on a typical z-score table gives the probability of the left tail, which is the chance that Z will be less than or equal to the z-score in question. (In case the question is asking for the probability that Z is greater than the z-score, subtract the value from table from 1.)

P(X\le 13) = P(Z \le 0.857143) \approx 0.8051.

"Technology" Approach

Depending on the manufacturer, the steps generally include:

  • Locate the cumulative probability function (cdf) for normal distributions.
  • Enter the lower and upper bound. The lower bound shall be a very negative number such as -10^{9}. For the upper bound, enter 13
  • Enter the mean and standard deviation (or variance if required).
  • Evaluate.

For example, on a Texas Instruments TI-84, evaluating \text{normalcdf})(-1\text{E}99,\;13,\;11.2,\;2.1 ) gives 0.804317.

As a result,

P(X\le 13) = 0.804317.

Number of green beans that are shorter than 13 centimeters:

Assume that the length of green beans for sale are independent of each other. The probability that each green bean is shorter than 13 centimeters is constant. As a result, the number of green beans out of 150 that are shorter than 13 centimeters follow a binomial distribution.

  • Number of trials n: 150.
  • Probability of success p: 0.804317.

Let Y be the number of green beans out of this 150 that are shorter than 13 centimeters. Y\sim\text{B}(150,0.804317).

The expected value of a binomial random variable is the product of the number of trials and the probability of success on each trial. In other words,

E(Y) = n\cdot p = 150 \times 0.804317 = 120.648\approx 121

The expected number of green beans out of this 150 that are shorter than 13 centimeters will thus be approximately 121.

7 0
3 years ago
A pet store has 9 puppies and 48 kittens.
Flauer [41]

that would be 48/9 because it would be kittens(48) to puppies(9) then simplified to 16/3.

5 0
3 years ago
Read 2 more answers
Consider the following expression and determine which statements are true. x^2+5yz−8
statuscvo [17]

Answer:

A.there are 3 terms.

B.the variables are x, y, and z.

Step-by-step explanation:

Complete question below:

Consider the following expression and determine which statements are true. x^2+5yz−8

CHOOSE 2 ANSWERS)

A.there are 3 terms.

B.the variables are x, y, and z.

C.The coefficient of x is 2.

D.the term 5yz is made up of 2 factors

The expression x^2+5yz-8

has three terms namely: x^2, 5yz and -8

The variables are x, y and z

The coefficient of x is 1 not 2, so option c is wrong

The term 5yz is made up of more than two factors namely 5, y, z, 5y, 5z, 5yz . So option d is also wrong.

The correct answers are option a and option b

A.there are 3 terms.

B.the variables are x, y, and z

8 0
3 years ago
Please help asap, its due in 20min
mojhsa [17]

Answer:

The scalar factor is 4/3

Step-by-step explanation:

The bottom of triangle B is 16 units, the bottom of triangle A is 12 units. So to find the scalar factor you have to divide B by A:

6/12=4/3

8 0
2 years ago
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