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Brums [2.3K]
3 years ago
10

All the pictures are in order for every question

Mathematics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer:

  1. C.) obtuse triangle
  2. 39°
  3. 167°
  4. D.) 111°

Step-by-step explanation:

1. The sum of angles in a triangle is 180°. The sum of the given angles is less than 90°, so the remaining angle must be more than 90°. When the largest angle is more than 90°, it is an obtuse angle. A triangle with an obtuse angle is classified as obtuse.

__

2. The sum of the interior angles is 180°, so we have ...

  x° +39° +102° = 180°

  x° = 39° . . . . . . . . . . . subtract 141°

__

3. The third interior angle is the supplement to the sum of the given interior angles. Likewise, x° is the supplement to the third interior angle, so its value is the same as the sum of the two given interior angles. (The rule is often stated as "an exterior angle is equal to the sum of the remote interior angles.")

  x° = 130° +37°

  x° = 167°

__

4. Same deal as problem 3:

  x° = 75° +36°

  x° = 111°

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The two answers are 23 and 47. You would subtract 24 from 70 then divide by 2 which would equal 23 then add the 24 back to it which is 47. 23 plus 47 equals 70.
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7. Krista wrote a list of factors and a list
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Step-by-step explanation:

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2 years ago
What expression is equivalent to 4(2x+3)
yuradex [85]

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2 years ago
There are 7 acts in a talent show.
lara31 [8.8K]

Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

          C(m,n)=\dfrac{m!}{n!(m-n)!}

         C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35

And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

Therefore the<em> probability of Event A</em> is:

           P(A)=1/35

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

           P(m,n)=\dfrac{m!}{(m-n)!}

         P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840

The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)

Therefore, <em>the probability of Event B</em> is:

            P(B)=1/840

7 0
3 years ago
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