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Brums [2.3K]
3 years ago
10

All the pictures are in order for every question

Mathematics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer:

  1. C.) obtuse triangle
  2. 39°
  3. 167°
  4. D.) 111°

Step-by-step explanation:

1. The sum of angles in a triangle is 180°. The sum of the given angles is less than 90°, so the remaining angle must be more than 90°. When the largest angle is more than 90°, it is an obtuse angle. A triangle with an obtuse angle is classified as obtuse.

__

2. The sum of the interior angles is 180°, so we have ...

  x° +39° +102° = 180°

  x° = 39° . . . . . . . . . . . subtract 141°

__

3. The third interior angle is the supplement to the sum of the given interior angles. Likewise, x° is the supplement to the third interior angle, so its value is the same as the sum of the two given interior angles. (The rule is often stated as "an exterior angle is equal to the sum of the remote interior angles.")

  x° = 130° +37°

  x° = 167°

__

4. Same deal as problem 3:

  x° = 75° +36°

  x° = 111°

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Select the relations that are functions.
Arlecino [84]

Answer:

Depending on how the input of each function defined,

  • The first choice \left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace,
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  • The fourth choice \left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

  • be defined for all elements in the domain, and
  • map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element a from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be \lbrace a,\, 6, \, C\rbrace. Similarly, the domain for the third and fourth relations should be \lbrace 1,\, 2, \, 3\rbrace and \lbrace a,\, b, \, c\rbrace

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Step-by-step explanation:

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3 years ago
The table below represents a linear function f(x) and the equation represents a function g(x):
Elza [17]

Answer:

(a) The slope of f(x) is greater than the slope of g(x)

(b) f(x) has a greater y intercept

Step-by-step explanation:

Given

\begin{array}{cc}x & {f(x)} & -1&-9&0&-1&1&7 \ \end{array}

g(x) = 3x - 2

Solving (a): Compare the slopes

The slope (m) of f(x) is calculated as;

m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

This gives:

m = \frac{f(0) - f(1)}{0 - 1}

m = \frac{f(0) - f(1)}{- 1}

Substitute values for f(0) and f(1)

m = \frac{-1 - 7}{- 1}

m = \frac{-8}{- 1}

m = 8

The slope of g(x) can be gotten using the following comparison

g(x) = mx + b

m \to slope

So:

g(x) = 3x -2

m = 3

m_{f(x)} > m_{g(x)}

Solving (b): Compare the y intercept

y intercept is when x = 0

From the table of f(x)

f(0) = -1

From the equation of g(x)

g(x) = 3x -2

g(0) = 3*0-2

g(0) =-2

<em></em>f(0) > g(0)<em></em>

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3 years ago
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