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Brums [2.3K]
3 years ago
10

All the pictures are in order for every question

Mathematics
1 answer:
ivanzaharov [21]3 years ago
7 0

Answer:

  1. C.) obtuse triangle
  2. 39°
  3. 167°
  4. D.) 111°

Step-by-step explanation:

1. The sum of angles in a triangle is 180°. The sum of the given angles is less than 90°, so the remaining angle must be more than 90°. When the largest angle is more than 90°, it is an obtuse angle. A triangle with an obtuse angle is classified as obtuse.

__

2. The sum of the interior angles is 180°, so we have ...

  x° +39° +102° = 180°

  x° = 39° . . . . . . . . . . . subtract 141°

__

3. The third interior angle is the supplement to the sum of the given interior angles. Likewise, x° is the supplement to the third interior angle, so its value is the same as the sum of the two given interior angles. (The rule is often stated as "an exterior angle is equal to the sum of the remote interior angles.")

  x° = 130° +37°

  x° = 167°

__

4. Same deal as problem 3:

  x° = 75° +36°

  x° = 111°

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Step-by-step explanation:

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The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).
Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

Vertices: (0,0)\ (1,0)\ (0,1)

Scale\ Factor = 3

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

New\ Vertex = Scale\ Factor * Old\ Vertex

For (0,0):

New\ Vertex = 3 * (0,0)

New\ Vertex = (3 * 0,3 * 0)

New\ Vertex = (0,0)

For (1,0):

New\ Vertex = 3 * (1,0)

New\ Vertex =  (3 * 1,3 * 0)

New\ Vertex =  (3,0)

For (0,1):

New\ Vertex =  3 * (0,1)

New\ Vertex =  (3 * 0,3 * 1)

New\ Vertex =  (0,3)

<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>

<em></em>

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4 years ago
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