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Andreyy89
3 years ago
9

Plz help if u can! i’ll mark brainlist! plz solve b. plz! ur worth every breath! <3

Mathematics
1 answer:
NikAS [45]3 years ago
5 0

Answer:

Step-by-step explanation:

3 times the number of yards is feet

let x represent the number of yards

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NORTH RIDGE MIDDLE SCHOOL collected 5,022 cans of food for food drive. Each of the 18 homerooms collected the same number of can
Diano4ka-milaya [45]

Answer:

5022 estimate= 5020  

18 estimate= 20

So, 5022/20

=251

Step-by-step explanation:

The questions says "about" so that means you have to estimate. First, you estimate the cans, then, you estimate the homerooms = 5022 and 20. Last, you have to divide, 5022/20

=251

Hope it helped!:)

4 0
3 years ago
You need
nika2105 [10]

Answer:

1. To convert cubic inches to cubic feet we divide the figure by 1728 (there are 1728 cubic inches in a cubic foot).

2. Measure the length, width and height of the box in inches. 2. Multiply the length, width and height and divide the resulting number by 1,728. This is the container's volume in cubic feet.

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3 years ago
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Jared has one pizza that has 12 slices. he wants to share his pizza with his two brothers. how many slices will each boy have if
zimovet [89]
Each brother should get 4 slices. 12 slices divided by 3 brothers equals 4 slices each.
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3 years ago
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Round the number to the thousandths place. 39,015.892491
BabaBlast [244]
The answer is 39,015.893
5 0
4 years ago
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Suppose you have a bag containing 15 red beads, 12 white beads and 8 black beads. You are going to draw one bead out of the bag.
iren [92.7K]

Answer:

probability that you draw a black bead or a white bead that is P(E1 U E2)

= 20/35 = 0.571

Step-by-step explanation:

Given a bag containing 15 red beads, 12 white beads and 8 black beads

n(S) = 15 + 12 +8 = 35

Let 'E1 be the event of selecting black beads and E2 be the event of selecting white beads

n(E1) = 8 and n(E2) = 12

Probability of draw a black bead P( E1 ) = \frac{n(E_{1} )}{n(S)}

                                                      P(E_{1}) = \frac{8}{35}

Probability of draw a white bead P( E2 ) = \frac{n(E_{2} )}{n(S)}

                                                    P(E_{2}) = \frac{12}{35}

probability that you draw a black bead or a white bead that is P(E1 U E2)

and E1 n E2 = ∅ (disjoint events)

<u>Axiom of union </u>

<u></u>P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - P(E_{1}nE_{2})\\<u></u>

E1 n E2 = ∅ ⇒ P(E1 n E2) = p(∅) = 0

P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - 0

P(E_{1}UE_{2} ) = \frac{8}{35} +\frac{12}{35}

P(E_{1}UE_{2} ) = \frac{20}{35}

P(E_{1}UE_{2} ) = 0.571

8 0
4 years ago
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