Answer:
The first 4 terms of the sequence are: 3, 9, 81, 6561
Step-by-step explanation:
We are given the following recursive function:
And the following initial condition:
The second term of the sequence is:
The third term of the sequence is:
The fourth term of the sequence is:
The first 4 terms of the sequence are: 3, 9, 81, 6561
Answer:
The given equations are;
x = (a + b)²
y = a² + 2·a·b + b²
z = a² + b² - 2·a·b
(a) The numerical coefficients of z terms are
1, 1, -2
The sum of the numerical coefficients = 1 + 1 - 2 = 0
(b) y + z is found by substituting the values of 'y' and 'z', in the expression y + z, as follows;
y + z = a² + 2·a·b + b² + a² + b² - 2·a·b = 2·a² + 2·b²
y + z = 2·a² + 2·b²
y - z = a² + 2·a·b + b² - (a² + b² - 2·a·b) = 4·a·b
(c) Given that a = 3, and b = -2, we have;
x = (a + b)² = a² + a·b + a·b + b² = a² + 2·a·b + b² = y
Therefore, x = y, for all values of 'a', and 'b'
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
(1+sinx)/cosx
(1+sin0)/cos0
(1+0)/1
1/1
1
:. Lim x->0 =1
Answer:
x - 3 > 10
Step-by-step explanation:
Let's solve for g.
gx=(−5(x−3))(2)
Step 1: Divide both sides by x.
gx
x
=
−10x+30
x
g=
−10x+30
x
Answer:
g=
−10x+30
x