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jok3333 [9.3K]
3 years ago
11

What's the slop of 2,-15 and 6,-45

Mathematics
1 answer:
NikAS [45]3 years ago
5 0

Answer:

Step-by-step explanation:

-15+45/2-6

30/-4

15/-2

-15/2

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I need help! anyone know this?
xz_007 [3.2K]
Yeah, x= 7/2 and y= -5/2
Please mark as brainliest and I hope this helps
5 0
3 years ago
Find the probability that a randomly selected point within the square falls in the blue shaded area (circle). r = 2 in [? ]% Rou
trasher [3.6K]

Answer:

78.5 %

Step-by-step explanation:

the probability = π(2)² / (4×4) ×100%

= 4π /16 × 100%

= π/4 ×100%

= (π×25)%

= 3.14 × 25 %

= 78.5 %

5 0
3 years ago
A city has 3 new houses for every 9 old houses. If there are 21 new houses in the city, how many old houses are there?
kipiarov [429]
To find your answer you would divide 21 by 3 which would be 7, once you've got 7 you would multiply it by 9 which would give you the amount of old houses that there is which would be 63.
5 0
3 years ago
Suponha que uma variável assume os valores: 11 – 8 – 7 – a – 16 – 10 Determine a de modo que a média aritmética seja igual 11.
Elenna [48]

Answer:

a = 14  

Step-by-step explanation:

The mean is the sum of the values divided by the number of values.

\begin{array}{rcl}\text{Mean}&= &\dfrac{11 + 8 + 7 + a + 16 + 10}{6}\\\\\dfrac{52 + a}{6}& = & 11\\52 + a & = & 66\\a & = & 66 - 52\\& = & \mathbf{14}\\\end{array}

4 0
4 years ago
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
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