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3 years ago

-Solve each equation. Example x+3=12 9+3=12

Mathematics

1 answer:

mash [69]3 years ago

7 0

$y + 9 = 9 | - 9 \\ y+ 9 - 9 = 9 - 9 \\ y = 0$

$10 + 2x = 20 | - 10 \\ 10 + 2x - 10 = 20 - 10 \\ 2x = 10 | \div 2 \\ 2x \div 2 = 10 \div 2 \\ x = 5$

$17 + 3c = 26 | - 17 \\ 17 + 3c - 17 = 26 - 17 \\ 3c = 9 | \div 3 \\ 3c \div 3 = 9 \div 3 \\ c = 3$

$x - 4 = 3 | + 4 \\ x - 4 + 4 = 3 + 4 \\ x = 7$

$2z - 7 = 7 | + 7 \\ 2z - 7 + 7 = 7 + 7 \\ 2z = 14 | \div 2 \\ 2z \div 2 = 14 \div 2 \\ z = 7$

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Answer:

$P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}$

Step-by-step explanation:

From the question, we have the following condition:

$p_1=p_2=1,\:and\:p_n=0$

We know that each student who hears the rumor tells it to a student picked at random from the dormitory (excluding, of course, himself/herself and the person from whom he/she heard the rumor)

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Consequently, the 4th student must not tell the 1st and second students.

$\implies p(4)=\frac{n-3}{n-2}\times \frac{n-4}{n-2}$

We can rewrite this to observe a pattern:

$\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^2}$

$\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^{4-2}}$

$\implies p(r)=\frac{(n-3)(n-4)(n-5)...(n-r)}{(n-2)^{r-2}}$

Hence, the probability that the rumor is told r times without coming back to a student who has already is:

$P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}$

See attachment for complete question

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4 years ago

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Let x = liters 20% solution to be added
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3 years ago

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Elan Coil [88]

Your answer is A. Michael can make fewer than 13 batches of cookies

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