JK + KL = JL
JK = 2x, KL = x + 2, JL = 5x - 10
therefore we heve the equation:
2x + (x + 2) = 5x - 10
3x + 2 = 5x - 10 |-2
3x = 5x - 12 |-5x
-2x = -12 |:(-2)
x = 6
JK = 2x → JK = 2(6) = 12
KL = x + 2 → KL = 6 + 2 = 8
JL = 5x - 10 → JL = 5(6) - 10 = 30 - 10 = 20
Check:
JK + KL = JL
12 + 8 = 20 CORRECT :)
Answer:
Lola was in lead for
of a mile.
Step-by-step explanation:
We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.
To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:




Therefore, Lola was in lead for
of a mile.
Answer is 2263.
Checkpoint 1 is -86
Checkpoint 4 is 2177
Subtract -86 from 2177....2177-(-86)
=2263
2263 is how much higher checkpoint 1 (-86) is from checkpoint 4 (2177)
Hope this helps! :)
Answer:
I'm leaning mostly towards C Because there is a solution, None of them are real numbers and if they were, S would = 5 Especially positive S
~ Zachary