H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
Answer:
528in
Step-by-step explanation:
SA formula: 2Lw + 2Lh + 2hw
for this box: 2(4×10)+2(10×16)+2(4×16)
2(40)+2(160)+2(64)
80+320+128
80+448
<u>528in</u>
Answer:
r≈2.26in
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
Step 1:
- 21w + 9 + 8w = - 5w - 5
Step 2:
- 13w + 9 = - 5w - 5
Step 3:
- 7w + 9 = - 5
Step 4:
- 7w = - 14
Step 5:
14 = 7w
Answer:
w = 2
Hope This Helps :)
The answer is B.
(the equation to solve this with is: a^2 + b^2 = c^2)