Question

What is the volume of the item described? An ice cream cone with a cone of radius 2 cm and height of 9 cm with a hemisphere of ice cream on top of radius 2 cm. Select the exact answer in terms of ​ π ​ and the approximate answer rounded to the nearest whole number

Answer 1

Volume of hemisphere = 2πr³/3
Volume of cone = πr²h/3

Where r = 2 and h = 9

Volume = volume of hemisphere + volume of cone
Volume = 2π(2)³/3 + π(2)²(9)/3
Volume = 16π/3 + 36π/3
Volume = 52π/3

Answer 2

Answer:

The volume of item is $\frac{52}{3}\pi$.

Step-by-step explanation:

The volume of cone

$V_1=\frac{1}{3}\pi r^2h$

Where r is radius of cone and h is the height of cone.

It is given that the radius of cone is 2 cm and the height of cone is 9 cm. So, the volume of cone is

$V_1=\frac{1}{3}\pi (2)^2(9)=12\pi$

The volume of hemisphere

$V_2=\frac{2}{3}\pi r^3$

Where r is radius of hemisphere.

It is given that the radius of hemisphere is 2 cm. So, the volume of hemisphere is

$V_2=\frac{2}{3}\pi (2)^3=\frac{16}{3}\pi$

The volume of ice cream is

$V=V_1+V_2$

$V=12\pi+\frac{16}{3}\pi$

$V=\frac{36+16}{3}\pi$

$V=\frac{52}{3}\pi$

Therefore the volume of item is $\frac{52}{3}\pi$.