Is (x + 7) a factor of f(x) = x^3 − 3x^2 + 2x − 8? Use either the remainder theorem or the factor theorem to explain your reason
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2 answers:
Answer:
Step-by-step explanation:
I don't think so. 7 is not a factor of 8, but let's try it and see.
x = - 7
f(-7) = (-7)^3 - 3(-7)^2 + 2(-7) + 8
f(-7) = -343 - 3(49) + 14 + 8
f(-7) = -484
The graph shows that the x intercept (the one you are interested in) takes place at a little over 3. The calculation shows that when x = -7, the y value is -484 which is nowhere's near 0.
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