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grigory [225]
3 years ago
12

What is the factored form of the expression over the complex numbers? 16x^2+9y^2

Mathematics
2 answers:
sertanlavr [38]3 years ago
8 0
I hope this helps you

noname [10]3 years ago
3 0

Answer: The factored form of the expression over the complex numbers is (4x+i3y)(4x-i3z)

Step-by-step explanation:

Since we have given that

16x^2+9y^2

We need to factorise the above equation.

As we know that

(a^2+b^2)=(a+ib)(a-ib)

16=4^2\\\\and\\\\9=3^2

and it can be written as

16x^2+9y^2=(4x)^2+(3y)^2=(4x+i3y)(4x-i3y)

Hence, the factored form of the expression over the complex numbers is

(4x+i3y)(4x-i3z)

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