Question

What is the factored form of the expression over the complex numbers? 16x^2+9y^2

Answer 1

I hope this helps you

Answer 2

Answer: The factored form of the expression over the complex numbers is $(4x+i3y)(4x-i3z)$

Step-by-step explanation:

Since we have given that

$16x^2+9y^2$

We need to factorise the above equation.

As we know that

$(a^2+b^2)=(a+ib)(a-ib)$

$16=4^2\\\\and\\\\9=3^2$

and it can be written as

$16x^2+9y^2=(4x)^2+(3y)^2=(4x+i3y)(4x-i3y)$

Hence, the factored form of the expression over the complex numbers is

$(4x+i3y)(4x-i3z)$