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jeka94
4 years ago
7

What is the value of the function f(x) = –x + 4 when x = –2?

Mathematics
2 answers:
wlad13 [49]4 years ago
5 0

Answer:

f(x) = 6

Step-by-step explanation:

f(x) = -(-2) +4

f(x) = 2 + 4

f(x) = 6.

9966 [12]4 years ago
4 0
F(x) = -x + 4
x = -2
-(x) = -(-2)
-x = 2
sub -x into the equation
f(x) = 2 + 4
f(x) = 6
f(-2)= 6
-2f = 6
-f = 3
f= -3
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Answer:

x = 136°

y = 44°

Step-by-step explanation:

x + 44° = 180° (Adjacent angles of a parallelogram)

x = 180° - 44°

x = 136°

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valkas [14]
<h3>Answer:  2/21</h3>

=========================================================

Explanation:

"Without replacement" means the card selected is not put back, and we do not put a copy of that card into the deck.

We have 5 yellow cards out of 5+9+1 = 15 cards total. The probability of picking yellow is 5/15 = 1/3. Let A = 1/3.

After picking that yellow card, we have 5-1 = 4 yellow left out of 15-1 = 14 total. The probability of picking another yellow card, after the first one is not replaced, is 4/14 which reduces to 2/7. Let B = 2/7.

Multiply the values of A and B

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3 0
4 years ago
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3 years ago
The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.
slamgirl [31]

Answer:

b=-6\\c=7

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}

substitute

y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Applying the distributive property convert to expanded form

y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})

y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)

y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7

y=x^2-6x+7

therefore

b=-6\\c=7

7 0
3 years ago
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