Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
The answer is P>9 The number line (if needed is)
Answer:
x= 13
Step-by-step explanation:
x + 8 = 21
x + 8-8 = 21-8
x = 13
Answer:
$97.65
Step-by-step explanation:
Hello
this equation is slope formula y=mx+b the m is x and b is Y so if it is saying 5/3 for x you use rise over run so i would be up 5 and over three and repeat that to make a line and the -4 is representing where your line should cross over the y axis
hope this helps
plz mark me as brainliest
