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3 years ago

In a geometric sequence, a2=2, a3=16, and a4=128.

Mathematics

1 answer:

Oduvanchick [21]3 years ago

4 0

Answer:

an = 1/4(8)^n-1

Step-by-step explanation:

Given the following in a geometric sequence, a2=2, a3=16, and a4=128.

nth term of a sequence = ar^n-1

a is the first term

r is the common ratio

r = a3/a2 = a4/a3

r = 16/2 = 128/16

r = 8

a2 = ar

2 = 8a

a = 2/8

a = 1/4

The nth term by substituting the parameters will be;

an = 1/4(8)^n-1

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3 years ago

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Answer:

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Step-by-step explanation:

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