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Effectus [21]
3 years ago
13

What is the area???????????

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0
The easiest thing to do here is to break up the figure into rectangles

Look at the attached images... will help solve

Hope this helps

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The equation is 2x+3 I need to know what x is
marysya [2.9K]

Answer:

2x is what x equals because you cant

Step-by-step explanation:

do anything with the equation

4 0
3 years ago
Identify the vertex of the graph of the given function y=2|x+13|-6
Brut [27]

x= 2/y   −10

x=−  2/ y  −16,

y≥−6

y=2(∣x+13∣−3)

3 0
3 years ago
Read 2 more answers
Given: x + 3.8 > -10.02. Choose the solution set. a. {x | x ∈ R, x > -6.22} b. {x | x ∈ R, x > -10.40} c. {x | x ∈ R, x
liberstina [14]
x+3.8 \ \textgreater \  -10.02 \\
x\ \textgreater \ -10.02 - 3.8 \\
x\ \textgreater \ -13.82 \\ \\
\{ x | x \in \mathbb{R}, x\ \textgreater \ -13.82 \}

The answer is C.
3 0
3 years ago
Which equation can be used to solve for in the following diagram?
Ivahew [28]

Answer:

the Answer is 3x+12)+X=180

5 0
3 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
Read 2 more answers
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