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Lady bird [3.3K]
2 years ago
14

Someone please help me with this question

Mathematics
2 answers:
lubasha [3.4K]2 years ago
7 0

Answer:

The actual answer is 2.26, but since that is not an option, I am going to say that you should choose the very last answer at the bottom, π r².

Step-by-step explanation:

Debora [2.8K]2 years ago
6 0

Answer:

  (c)  4 in

Step-by-step explanation:

The area of a circle is given by the formula ...

  A = πr²

Filling in the given values, we have ...

  16π in² = πr²

Dividing by π gives ...

  16 in² = r²

Taking the square root, we find ...

  r = √(16 in²) = 4 in

The radius of the circle is 4 inches.

You might be interested in
What two numbers multiply to 120 and add to -26
Arisa [49]
The two numbers are -6 and -20

-20 x -6 = 120

-20 + (-6) = -26


3 0
3 years ago
For each figure answer the following questions
Rudiy27

9514 1404 393

Answer:

  a) ∆ABC ~ ∆EDC by AA similarity

  b) ED/AB = 3/4

  c) 15 cm

Step-by-step explanation:

a) Two angles in each triangle are the same, so the AA similarity postulate can be used to declare the ∆ABC ~ ∆EDC. (Each triangle includes a right angle and angle C.)

__

b) Corresponding sides are ED/AB, DC/BC, EC/AC. The ratio of corresponding sides is ED/BC = (12 cm)/(16 cm) = 3/4.

__

c) Using the ratios identified above, we have ...

  DC/BC = 3/4 = x/(20 cm)

  x = 3/4(20 cm)

  x = 15 cm

8 0
3 years ago
The table shows the height of 5 students in inches what is the mean absolute deviation for these numbers
german

Answer:

4

Step-by-step explanation:

To find the mean absolute deviation (MAD), first find the mean (or average).

μ = (59 + 71 + 68 + 75 + 67) / 5

μ = 68

Next, subtract the mean from each value and take the absolute value.

|59 − 68| = 9

|71 − 68| = 3

|68 − 68| = 0

|75 − 68| = 7

|67 − 68| = 1

Sum the results and divide by the number of students.

MAD = (9 + 3 + 0 + 7 + 1) / 5

MAD = 4

3 0
3 years ago
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
(08.01, 08.02, 08.03, 08.05, 08.06 MC)
fenix001 [56]
Is it x times 2 times y times 2? is that what it is asking or is it meaning squared
6 0
3 years ago
Read 2 more answers
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