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kherson [118]
3 years ago
10

A statistics instructor wants to see if allowing students to use a notecard on exams will affect their overall exam scores. The

instructor thinks that the results could be affected by the type of class: traditional, Web-enhanced, or online. He randomly selects half of his students from each type of class to use notecards. At the end of the semester, the average exam grades for those using notecards is compared to the average for those without notecards.
Required:
a. What type of experimental design is this?
b. What is the response variable in this experiment?
c. What is the factor that is set to predetermined levels? What are the treatments?
d. Identify the experimental units.
Mathematics
1 answer:
likoan [24]3 years ago
8 0

Answer:

Throughout the clarification section elsewhere here, the definition of the concern is discussed.

Step-by-step explanation:

  • This seems to be an experimental analysis where the students were purposely administered an assessment and treatment of someone using notecards towards examine a potential improvement in the answer or calculated indicator that is average scores.
  • Overall test scores are the answer component.
  • Through the use of notecards seems to be the explanatory component. The vector degree is 'Used' either 'Not Used.'
  • The participants offering the test seem to be the experimental groups.
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EleoNora [17]

Answer:

students in the drama club: 57

students in the yearbook club: 44

Step-by-step explanation:

101 - 13 = 88

88 / 2 = 44

101 - 44 = 57

44 in the drama club and 57 in the yearbook club

5 0
2 years ago
The formula to determine energy is uppercase E = one-half m v squared. What is the formula solved for v?
alexandr402 [8]

Answer:

Step-by-step explanation:

E=\frac{1}{2}mv^2

All the variables on the right are being multiplied together then the whole mess is being divided by 2.  Let's get rid of the 2 first.  The undoing of division is multiplication, so we will begin by multiplying both sides by 2 to get

2E=mv^2

Next we will move the m. The undoing of multiplication is division.  So we divide both sides by m to get

\frac{2E}{m}=v^2

The undoing of a square is to take the square root, so we will do that to both sides giving us, finally

\sqrt{\frac{2E}{m} }=v

6 0
3 years ago
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HELP!!!
uranmaximum [27]

Step-by-step explanation:

10 gallons of gas is $29.50

10 gallons of gas = $29.50

10 gallons of gas / 10 = $29.50 / 10

1 gallon of gas = $2.95

Per x gallons of gas,

1 gallon of gas * x = $2.95 * x

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3 years ago
What equation results from completing the square and then factoring? x^2+24x=33
Nezavi [6.7K]

Answer:

Its C but the way I got is too small so I cant really give explanation

7 0
3 years ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

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3 years ago
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