There is one critical point at (2, 4), but this point happens to fall on one of the boundaries of the region. We'll get to that point in a moment.
Along the boundary 
, we have
which attains a maximum value of
Along 
, we have
which attains a maximum of
Along 
, we have
which attains a maximum of
So over the given region, the absolute maximum of 
is 1578 at (2, 44).
Answer:
y = -4/5x + 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Standard Form: Ax + By = C
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
Standard Form: 4x + 5y = 20
<u>Step 2: Rewrite</u>
- Subtract 4x on both sides: 5y = 20 - 4x
- Divide 5 on both sides: y = 4 - 4/5x
- Rearrange: y = -4/5x + 4
Area for triangles is 1/2b * h.
If 8m were the height, then the area is 24 sq m.
If 6m were the height, then the area is still 24 sq m.
The area is 24 sq m.
Hope this helps! Have a great day :)
Answer:
about 31 percent
Step-by-step explanation:
18+6x?= 168
try taking away the 18 and 6 then dividing it
