Answer:
interquartile range of original data:20
New data:15
Step-by-step explanation:
The original data is given as:
45 65 70 80 85 100.
lower quartile(
)=65
median of data(
)=(70+80)/2=75
upper quartile(
)=85
interquartile range=
-![Q_{1}](https://tex.z-dn.net/?f=Q_%7B1%7D)
=85-65=20
The changed data is given as:
65 70 80 85
lower quartile(
)=(65+70)/2=67.5
median(
)=(70+80)/2=75
upper quartile(
)=(80+85)/2=82.5
interquartile range=
-![Q_{1}](https://tex.z-dn.net/?f=Q_%7B1%7D)
=82.5-67.5=15.
A. The number of different colors on the page - is the statement that contains a variable.
The rest are all fixed values. 27 points. 80 miles per hour. half the speed of the car.
His model is incorrect because 20 x 7 is not 14, it is 140. If he had 140 instead of 14, he would have been correct.
I haven't done division like that in a long time, so this is what I think it will look like. I didn't add other work (multiplying 4 with #'s) but you can if you have to
Answer:
W=2001.24 newton meters
Caution: check units and arithmetic - I often make errors.
Step-by-step explanation:
Work is force times distance.
Denote height by h where h=0 is at ground level.
Denote the mass of the bucket and rope at height h by m(h).
The rate at which the bucket loses mass with height is (20-16)/10=0.4 kg/m
The rate at which the rope between the bucket and the top of the building loses mass is 0.4 kg/m
The initial mass of the bucket and rope is
![m_{0}=20+0.4+0.4(10)=24.4](https://tex.z-dn.net/?f=m_%7B0%7D%3D20%2B0.4%2B0.4%2810%29%3D24.4)
The mass at height h is
![m(h)=24.4-0.8h](https://tex.z-dn.net/?f=m%28h%29%3D24.4-0.8h)
The force required at height h is
m(h)g
where g is the gravitational acceleration.
g=9.81 meters/sec/sec
The work required is
![\int\limits^b_a {m(h)g} \, dh](https://tex.z-dn.net/?f=%5Cint%5Climits%5Eb_a%20%7Bm%28h%29g%7D%20%5C%2C%20dh)
Where a=0 and b=10
![g\int\limits^b_a {(24.4-0.8h)} \, dh=g(24.4h-0.4h^2)\left \{ {{10} \atop {0}} \right.](https://tex.z-dn.net/?f=g%5Cint%5Climits%5Eb_a%20%7B%2824.4-0.8h%29%7D%20%5C%2C%20dh%3Dg%2824.4h-0.4h%5E2%29%5Cleft%20%5C%7B%20%7B%7B10%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
g(244-40)=204g
W=2001.24 newton meters
Answer:
Blue (the first)
Step-by-step explanation: