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ratelena [41]
3 years ago
13

Help me step by step 6×+5=29

Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0
First you subtract 5 from each side. so its 6x+5=29                                                                      -5  -5which then you get 6x=24. You then divide 6 from 24 and you get x=4 
Len [333]3 years ago
7 0
6x+5=29
-5. -5
6x=. 24
6x/6=X
24/6=4
X=4
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3x+2y=18 , 8x+6y=50 if x represents the cost of a birthday card and y represents the cost of a thank you note how much does each
elena55 [62]

(-9x-6y=-54) +(8x+6y=50)= -x=-4; x=4
3(4)+2y=18
12+2y=18
2y=6 ; y=3
Each birthday card costs 4

7 0
4 years ago
Determine the vertex form of g(x) = x^2 + 2x – 1. Which graph represents g(x)?
nataly862011 [7]

Answer:

Graph D

Step-by-step explanation:

Move the constant to the opposite side of the equation and group terms that include the same variable.

g(x) + 1 = x^2 + 2x

Finish the square. Remember to keep the equation balanced by using the same constants on both sides.

g(x) + 1 + 1 = x^2 + 2x + 1

g(x) + 2 = x^2 + 2x + 1

Rewrite as perfect squares

g(x) + 2 = (x + 1)^2

Equation in vertex form:
g(x) = (x + 1)^2 - 2

The vertex:

(-1, -2)

* This a minimum *

  • <em>(Parabola open upward)</em>
3 0
2 years ago
What is the remainder when 62,710 is decided by 541
Mamont248 [21]

Answer:

the quotient is is 115.915 and the remainder is 495

Step-by-step explanation:

Hope it helps you

Mark my answer as brainlist

have a nice day

7 0
3 years ago
Angela needs to find the volume of the sphere shown below. Which formula should she use?
Zepler [3.9K]

Answer:

v = (4/3)(pi)(r^3)

Step-by-step explanation:

7 0
3 years ago
Use truth tables to show that the following statements are logically equivalent. ∼ P ⇔ Q = (P ⇒∼ Q)∧(∼ Q ⇒ P)
Alina [70]

Answer:  The given logical equivalence is proved below.

Step-by-step explanation:  We are given to use truth tables to show the following logical equivalence :

∼ P ⇔ Q ≡ (P ⇒∼ Q)∧(∼ Q ⇒ P)

We know that

two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

The truth table is as follows :

P     Q     ∼ P     ∼Q   ∼ P⇔ Q    P ⇒∼ Q    ∼ Q ⇒ P     (P ⇒∼ Q)∧(∼ Q ⇒ P)

T     T         F        F             F            F                   T                       F

T     F         F        T             T             T                   T                       T

F     T         T        F             T            T                   T                       T

F     F         T        T             F            T                   F                       F

Since the corresponding truth vales for ∼ P ⇔ Q and (P ⇒∼ Q)∧(∼ Q ⇒ P) are same, so the given propositions are logically equivalent.

Thus, ∼ P ⇔ Q ≡ (P ⇒∼ Q)∧(∼ Q ⇒ P).

8 0
3 years ago
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