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Akimi4 [234]
3 years ago
10

If i got a 19/25 answers right on a test what would be my test score

Mathematics
2 answers:
JulijaS [17]3 years ago
6 0
76% would be your test score
NemiM [27]3 years ago
4 0
STEP 1
we think of 100 as a perfect score; divide 100 by bottom number

= 100 ÷ 25
= 4


STEP 2
multiply top number by step 1 answer

= 4 * 19
= 76


ANSWER: 19/25 is equivalent to a 76

Hope this helps! :)
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It is written as:

6.9 × 10^{-4}
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3 years ago
Which is a rule that describes the translation of a point from (–5, 4) to (–1, 2)?
Ket [755]

Answer:

B

Step-by-step explanation:

Given the translation (- 5, 4 ) → (- 1, 2 )

Note the x- coordinate of the translation is 4 more than the x- coordinate of the original x- coordinate, that is - 5 → - 1 is + 4

The y- coordinate of the translation is 2 less than the y- coordinate of the original y- coordinate, that is 4 → 2 is - 2

Thus the translation rule is

(x, y ) → (x + 4, y - 2 ) → B

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The square of a number, decreased by 15, is equal to twice the number
STALIN [3.7K]
the answer to this equation x^2-15=2x
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Find the solution the each of the following first order linear differential equations:
Cerrena [4.2K]

Answer:

a. y=\frac{2}{3}x^7+cx^4

b. y=2e^{7x}-ce^{5x}

c. y=e^{-2x}arctan(e^{2x})+ce^{-2x}

d. i=e^{-2t}\left(\frac{8\left(3e^{2t}\sin \left(3t\right)+2e^{2t}\cos \left(3t\right)\right)}{13}+C\right)

Step-by-step explanation:

a) xy' -4y = 2 x^6

xy'-4y=2x^6\\y'-\frac{4}{x}y=2x^5\\p(x)=\frac{-4}{x}\\Q(x)=2x^5\\\mu(x)=\int P(x)dx=\int \frac{-4}{x}dx=Ln|x|^{-4}\\y=e^{-\mu(x)}\int {e^{\mu(x)}Q(x)dx}\\y=x^4 \int {x^{-4}2x^6}dx\\y=\frac{2}{3}x^7+cx^4

 

b) y' - 5y = 4e^7x

y'-5y=4e^{7x}\\p(x)=-5\\Q(x)=4e^{7x}\\\mu(x)=\int P(x)dx=\int-5dx=-5x\\y=e^{-\mu(x)}\int {e^{\mu(x)}Q(x)dx}\\y=e^{5x}\int {e^{-5x}4e^{7x}}dx\\y=2e^{7x}-ce^{5x}

c) dy/dx + 2y = 2/(1+e^4x)

\frac{dy}{dx}+2y=\frac{2}{1+e^{4x}}\\p(x)=2\\Q(x)=\frac{2}{1+e^{4x}}\\\mu(x)=\int P(x)dx=\int 2dx=2x\\y=e^{-\mu(x)}\int {e^{\mu(x)}Q(x)dx}\\y=e^{-2x}\int {e^{2x}\frac{2}{1+e^{4x}}}dx\\y=e^{-2x}arctan(e^{2x})+ce^{-2x}

d) 1/2 di/dt + i = 4cos(3t)

\frac{1}{2}\frac{di}{dt}+i=4cos(3t)\\\frac{di}{dt}+2i=8cos(3t)\\p(t)=2\\Q(t)=8cos(3t)\\\mu(t)=\int P(t)dt=\int 2dt=2t\\i=e^{-\mu(t)}\int {e^{\mu(t)}Q(t)dt}\\i=e^{-2t}\int {e^{2t}8cos(3t}dt\\i=e^{-2t}\left(\frac{8\left(3e^{2t}\sin \left(3t\right)+2e^{2t}\cos \left(3t\right)\right)}{13}+C\right)

3 0
3 years ago
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inessss [21]

Answer:

0.58

Step-by-step explanation:

P1 > 1 = 5/6

P2 > 1 = 5/6

P3 > 1 = 5/6

P1*P2*P3 = 5/6*5/6*5/6

P = 0.58

8 0
3 years ago
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