Answer:
5x2y2 is the GCF common factor of the following terms.
Given expression is
![\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%5Cfrac%7B16x%5E%7B11%7Dy%5E8%7D%7B81x%5E7y%5E6%7D%7D)
Radical is fourth root
first we simplify the terms inside the radical


So the expression becomes
![\sqrt[4]{\frac{16x^4y^2}{81}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%5Cfrac%7B16x%5E4y%5E2%7D%7B81%7D%7D)
Now we take fourth root
![\sqrt[4]{16} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%202)
![\sqrt[4]{81} = 3](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%7D%20%3D%203)
![\sqrt[4]{x^4} = x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E4%7D%20%3D%20x)
We cannot simplify fourth root (y^2)
After simplification , expression becomes
![\frac{2x\sqrt[4]{y^2}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5Csqrt%5B4%5D%7By%5E2%7D%7D%7B3%7D)
Answer is option B
Answer:

Step-by-step explanation:

Answer:
The area of triangle for the given coordinates is 1.5
Step-by-step explanation:
Given coordinates of triangles as
A = (0,0)
B = (3,4)
C = (3,2)
So, The measure of length AB = a = 
Or, a = 
Or, a = 
Or, a = 
∴ a = 5 unit
Similarly
The measure of length BC = b = 
Or, b = 
Or, a = 
Or, b = 
∴ b = 2 unit
And
So, The measure of length CA = c = 
Or, c = 
Or, c = 
Or, c = 
∴ c =
unit
Now, area of Triangle written as , from Heron's formula
A = 
and s = 
I.e s = 
Or. s = 
So, A = 
Or, A = 
Or, A =
× 
∴ Area of triangle = 1.5
Hence The area of triangle for the given coordinates is 1.5
Answer