Answer:
The answer to your questions is below
Step-by-step explanation:
4.-
In a 45°-45°-90° triangle, the length of the legs are "x" and the length of the hypotenuse is x
Then, in this problem, the length of the leg is 7 then the length of the hypotenuse will be 7
5.- In a 30°-60°-90° triangle, the length of the hypotenuse is 2x, the length of the longer leg is x
and the length of the shorter leg is x.
In this problem we have the length of the hypotenuse = 20 and find x.
2x = 20
x = 20/2
x = 10
longer leg = x
6.- nonzero
7.- hypotenuse = 20 cm
Find x
2x = 20
x = 20/2
x = 10
Shoter leg = x = 10 cm
Answer:
242 cm
Step-by-step explanation:
1. Find the scale factor
A scale factor (SF) is the ratio of two corresponding lengths in similar figures.
SF = actual distance/scale distance
If the scale width is 3.8 cm,
SF = 418 cm/3.8 cm = 110
2. Calculate the actual depth
110 = actual depth/2.2 cm
Actual depth = 110 × 2.2 cm = 242 cm
Answer:
first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.
we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)
an = a1 + (n-1) * d
n = the term we want to find = 34
a1 = first term = 3
d = common difference = 6
now we sub
a34 = 3 + (34-1) * 6
a34 = 3 + (33 * 6)
a34 = 3 + 198
a34 = 201
now we use the sum formula
Sn = (n (a1 + an)) / 2
S34 = (34(3 + 201))/2
s34 = (34(204)) / 2
s34 = 6936/2
s34 = 3468 <=== the sum of the first 34 terms:
Answer:
x=50
Step-by-step explanation:
note that 40% is 2/5
Therefore, 30 tomatoes is 1- 2/5 = 3/5
3/5 of the tomatoes last year is 30
lets say tomatoes = x
3/5 x = 30
divide by 3 on both sides
1/5 x = 10
multiply by 5 on both sides
x=50
:D
hope it helped :D
Answer:
P(Y=1|X=3)=0.125
Step-by-step explanation:
Given :
p(1,1)=0
p(2,1)=0.1
p(3,1)=0.05
p(1,2)=0.05
p(2,2)=0.3
p(3,2)=0.1
p(1,3)=0.05
p(2,3)=0.1
p(3,3)=0.25
Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)
P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)
P(X=3)=p(3,1) +p(3,2) +p(3,3)
P(X=3)=0.05+0.1+0.25=0.4
Hence P(Y=1|X=3)=0.125
