Draw a triangle with verticesA(0,4),B(2,-2),andC(-2,-2).

Jessica is a custodian at Oracle Arena. She waxes 20 m² of the floor in = of an hour. Jessica

Wewaii [24]

The complete question is as follows:

Jessica is a custodian at Oracle Arena. She waxes 20 $\mathbf{m^{2}}$ of the floor in $\mathbf{\frac{3}{5}}$ of and hour. At this rate, how many square meters can she wax per hour ?

Answer:

$\mathbf{\frac{100}{3}\approx33.33 \ m^{2} \ per \ hour}$

Step-by-step explanation:

$\textrm{rate}=\frac{\textrm{Area waxed in square meter}}{\textrm{Time taken to wax in hours}}$

$\textrm{rate}=\frac{20 \ \textrm{m}^{2}}{\frac{3}{5} \ \textrm{hours}}$

$\textrm{rate}=\frac{20\times5}{3}$

$\mathbf{rate=\frac{100}{3}\approx33.33 \ m^{2} \ per \ hour}$

8 0

3 years ago

Which equation has a graph that passes through the points at (0,5) and (-3,-4)?

Roman55 [17]

Answer:

$y = 3x + 5$

Step-by-step explanation:

We are asked the equation of the graph which passes through the points at (0,5) and (-3,-4).

Now, we know that the equation of a straight line passing through the points ( $x_{1},y_{1}$ ) and ( $x_{2},y_{2}$ ) is given by

$\frac{y - y_{1}}{y_{1} - y_{2}} = \frac{x - x_{1}}{x_{1} - x_{2}}$ .

So, in our case ( $x_{1},y_{1}$ ) ≡ (0,5) and ( $x_{2},y_{2}$ ) ≡ (-3,-4)

Therefore, the equation of the straight line will be

$\frac{y - 5}{5 - (- 4)} = \frac{x - 0}{0 - (- 3)}$

⇒ $y - 5 = \frac{9}{3}x$

⇒ $y = 3x + 5$ (Answer)

4 0

3 years ago

Holiday items are on sale at 15% off the original retail price. If tree lights are regularly $12.40 per set, what is the sale pr

Umnica [9.8K]

12.40*(100-15)=10.54
$10.54 cents is the new cost

6 0

3 years ago

Read 2 more answers

Simplify

OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

$\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}$

we need to simplify that

$x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)$

so we can continue

$\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}$

and we can put all together

$\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}$

3 0

3 years ago

I need help with this Maths Homework Question.

Monica [59]

Answer:

1. 41/45.

2. x/(x^2+3x+6)

Step-by-step explanation:

1.

So first we fill the ven diagram.

There are 240 in band, so we fill that. 60 students are in both, we put that in the middle, and there are 110 people in choir.

now, since we want the probability that a student is chosen that is in band, and choir, and both. We add all this up

240 + 60 + 110 = 410.

The total possible outcome is 410, and the total outcome is 450, so the answer is

410/450 = 41/45

2.

First, to get the total outcomes, we have to add all the expressions together.

x(x-2) + x + 2x+8 = x^2 - 2 + x + 2x + 8 = x^2 - 2 + 3x + 8 = x^2 + 3x + 6.

Since that is the total outcome, we have to find the possible outcomes.

The problem wants BOTH from the 20th century and British, so it is x.

x/(x^2+3x+6). We cannot simplify any further, thus x/(x^2+3x+6) is our answer

3 0

2 years ago