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pogonyaev
3 years ago
10

Plz help me on this​

Biology
1 answer:
Scrat [10]3 years ago
4 0
Active transport because the movement of molecules is going across the cell membrane (that should be right?)
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The gene frequency for a dominant allele is 0.68 and the recessive allele is 0.39. What percent of the population has a homozygo
Alinara [238K]

Answer:

15.21 %

Explanation:

If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:

p + q = 1

p² + 2pq + q² = 1

where;

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

p² = percentage of homozygous dominant individuals

q² = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

Given that p= 0.68 and q = 0.39

the percentage of the homozygous recessive genotype (q² ) will be

(0.39)² = 0.1521

= 0.1521 × 100

= 15.21 %

∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %

5 0
3 years ago
Do back dimples mean your good in bed?
sineoko [7]
How good you are in bed relies only on you as a person and what you do, not on physical features. Anybody that says you are (or aren't) is just stating some sort of stereotype at best
6 0
3 years ago
Who used the word cell for the structures he observed when he examined a piece of cork under the microscope?
Lerok [7]

This was Robert Hooke.

4 0
3 years ago
The presence of freckles is due to a dominant allele. four percent of the individuals in a particular population lack freckles.
vaieri [72.5K]

Let us assign the recessive allele for freckle to be f and the dominant F. According to the statement, we deduce that ff = 0.04.

The frequency of the recessive f allele is, therefore, is 0.2 (square root of 0.04 ).

Hardy-Weinburg p + q = 1

P + 0.2 = 1; p = 1- 0.2 = 0.8

Therefore using the Hardy-Weinburg equation of a population in equilibrium

P2+2pq+q2=1

Heterozygous individuals are;

2pq = 2*0.8*0.2 = 0.32

This is 32% of the population






7 0
3 years ago
Read 2 more answers
7.   Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. If
Oksi-84 [34.3K]

Hi!

The correct answer would be A.

<h3>Explanation:</h3>

As the allele P for polka dot is dominant to the allele p for solid color, it would yield a Polka dot tail in the individual in the presence of just one allele of P, while masking the effect of p for solid color.

So the possible genotypes and phenotypes would be as follows:

  1. PP (Polka dot tail)
  2. Pp (Polka dot tail)
  3. pP (Polka dot tail)
  4. pp (Solid color tail)

Following a cross by two heterozygous individuals, there would be 25 percent chance (1/4) of having the genotype pp , 25 percent (1/4) chance of having the genotype PP and 50 percent (2/4) chance of having the genotype Pp.

But the phenotype yielded by Pp and PP offspring would be polka dots, so there is a 75 percent (3/4) chance of having polka dot offspring, and 25 percent chance of having solid colored tail offspring.

<h3>Hope this helps!</h3>
6 0
3 years ago
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