Answer: The electron transport chain.
Explanation:
Cellular respiration is defined as the mechanism by which living organisms converts organic substances from food such as glucose with the use of oxygen into energy-carrying biomolecules (e.g. adenosine triphosphate or ATP). There are different stages of cellular respiration which includes:
--> glycolysis,
--> pyruvate oxidation,
--> the citric acid or Krebs cycle, and
--> oxidative phosphorylation.
The oxidative phosphorylation also referred to as the ELECTRON TRANSPORT CHAIN occurs in the inner membrane of the mitochondria. It transfers electrons donated by the reduced electron carriers NADH and FADH2 (obtained from glycolysis, the citric acid cycle or fatty acid oxidation) through a series of electrons acceptors, to oxygen.
The electron transport chain is said to produces most of the energy which is 34 ATP molecules, as compared to only 2 ATP for glycolysis and 2 ATP for Krebs cycle.
Answer:
scientific method: A method of discovering knowledge about the natural world based on making falsifiable predictions (hypotheses)
Explanation:
Opinion ko lng yan hahaha
I think A is the right answer because secondary consumers are herbivores. I am 99.9% sure about this.
Answer:
Hidrólisis y oxidación.
Explicación:
La hidrólisis y la oxidación son las reacciones que ocurren en el paso del alfacetoglutarato a succinato. En el quinto paso hay una hidrólisis del grupo tioéster de CoA en la que los átomos de los compuestos se rompen y luego sustituyen sus elementos miembros. Esta reacción de hidrólisis libera energía y se hace un ATP a partir de ADP. En el paso 6, succinato a fumarato es una oxidación para poner en el doble enlace significa que FAD se reduce a FADH2. Entonces podemos decir que la hidrólisis y la oxidación son las reacciones que ocurren en el paso de Alfacetoglutarato a succinato.
Answer:
Polypeptides are composed of amino acids, and we know amino acids are differently charged, have different R groups, and also have different isoelectric points. Depending on different isoelectric points and charged groups, the polypeptides can be separated and because a protein has its lowest solubility on its isoelectric point.
So in this question,
(a) (Lys-Ala)3 ; this is highly positively charged (polar) at pH 7 than (Gly)20 which is uncharged except for the amino and carboxyl terminal.
(b) (Glu)20 ; it is highly negatively charged at pH 7 whereas (Phe-Met)3 is much less polar and hence less soluble.
(c) (Asn-Ser-His)5 ; at pH 3, because in (Ala-Asp-Gly)5 the carboxylate groups of Asp residues are partially protonated and neutral, whereas in (Asn-Ser-His)5 , the imidazole groups of His residues are fully protonated and positively charged.
(d) (Asn-Ser-His)5; at pH 6.0; both polymers have polar Ser sidechains, but (Asn-Ser-His)5 also has the polar Asn side chains and partially protonated His side chains.
Explanation:
