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Maksim231197 [3]
3 years ago
8

How do you solve 4x+2y=10 x-y=13 using substitution

Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0

\left \{ {{4x+2y=10} \atop {x-y=13}} \right.

x=13+y

4(13+y)+2y=10

52+4y+2y=10

6y=-42

y=-\frac{42}{6}=-7

y=-7

x=13-7=6

<span>\left \{ {{x=6} \atop {y=-7}} \right.</span>

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