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kobusy [5.1K]
3 years ago
13

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

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X+y=5<br> x×y=6<br> Solve simultaneously with steps
igor_vitrenko [27]

Answer:

(3, 2), (2, 3)

Step-by-step explanation:

x + y = 5

xy = 6

Solve the first equation for x.

x = 5 - y

Substitute 5 - y for x in the second equation.

xy = 6

(5 - y)y = 6

5y - y² = 6

y² - 5y + 6 = 0

Factor.

(y - 2)(y - 3) = 0

y - 2 = 0  or y - 3 = 0

y = 2  or y = 3

Now substitute 2 for y in the first equation and solve for x.

x + y = 5

x + 2 = 5

x = 3

One solution is x = 3; y = 2, or (3, 2).

Now substitute 3 for y in the first equation and solve for x.

x + y = 5

x + 3 = 5

x = 2

Another solution is x = 2; y = 3, or (3, 2).

Answer: (3, 2), (2, 3)

7 0
2 years ago
A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

C = Children; S = Students; A = Adults

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For the tickets sold, we have:

5C + 7S + 12A = 2388

Half as many as adults are children implies that:

A = \frac{C}{2}

Required

Solve for A, C and S

The equations to solve are:

C + S + A = 329 -- (1)

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A = \frac{C}{2} -- (3)

Make C the subject in (3)

C = 2A

Substitute C = 2A in (1) and (2)

C + S + A = 329 -- (1)

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Make S the subject

S = 329 - 3A

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5*2A + 7S + 12A = 2388

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7(329 - 3A) + 22A = 2388

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A = 2388 - 2303

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C = 2 * 85

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Recall that: S = 329 - 3A

S = 329 - 3 * 85

S = 329 - 255

S = 74

Hence, the result is:

C = 170

S = 74

A = 85

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